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\(\dfrac{-4}{11}\) = \(\dfrac{x}{22}\) = \(\dfrac{40}{y}\)
\(x\) = -\(\dfrac{4}{11}\).22 = -8
y = 40 :( -\(\dfrac{4}{11}\))
y = - 110
Vậy (\(x\);y) =(-8; -110)
\(\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{y}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{x}{22}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{-4\cdot2}{11\cdot2}=\dfrac{-8}{22}\)
\(\Rightarrow\dfrac{-8}{22}=\dfrac{40}{y}\)
\(\Rightarrow\dfrac{-8}{22}=\dfrac{-8\cdot\left(-5\right)}{22\cdot\left(-5\right)}=\dfrac{40}{-110}\)
\(\Rightarrow\dfrac{-4}{11}=\dfrac{-8}{22}=\dfrac{40}{-110}\)
\(\Rightarrow\left(x,y\right)=\left(-8;-110\right)\)
ta có: 311>256=>311/256>1=>-311/256<-1
199<203=>199/203<1=>-199/203>-1
=>-311/256<199/203
\(\frac{18}{91}=\frac{558}{2821}\)
\(\frac{6}{31}=\frac{546}{2821}\)
=>\(\frac{18}{91}>\frac{6}{31}\)
Ta có : \(\frac{18}{91}< \frac{18}{90}\left(91>90\right)\)
\(\Rightarrow\frac{18}{91}< \frac{1}{5}\left(1\right)\)
\(\frac{6}{31}>\frac{6}{30}\left(31>30\right)\)
\(\Rightarrow\frac{6}{31}>\frac{1}{5}\left(2\right)\)
Từ \(\left(1\right);\left(2\right)\Rightarrow\frac{18}{91}< \frac{1}{5}< \frac{6}{31}\)
\(\Rightarrow\frac{18}{91}< \frac{6}{31}\)
Chúc bạn học tốt !!!
a) \(\dfrac{-1}{-4}\)=\(\dfrac{1}{4}>0\)
\(\dfrac{3}{-4}< 0\)
\(\Rightarrow\dfrac{1}{4}>\dfrac{3}{-4}hay\dfrac{-1}{-4}>\dfrac{3}{-4}\)
b) Ta có:
\(\dfrac{15}{17}=1-\dfrac{2}{17}\\ \)
\(\dfrac{25}{27}=1-\dfrac{2}{27}\\ \\ \)
Mà \(\dfrac{2}{17}>\dfrac{2}{27}\left(17< 27\right)\)
\(\Rightarrow1-\dfrac{2}{17}< 1-\dfrac{2}{27}\)hay \(\dfrac{15}{17}< \dfrac{25}{27}\)
\(\dfrac{311}{256}\) và \(\dfrac{199}{203}\)
Ta dùng cách so sánh 2 phân số với 1:
\(\dfrac{311}{256}>1\) \(;\) \(\dfrac{199}{203}< 1\)
Vậy ta có: \(\dfrac{311}{256}>1>\dfrac{199}{203}\)
Vậy \(\dfrac{311}{256}>\dfrac{199}{203}\)
311/256 > 199/203