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\(a,\dfrac{1}{7}và\dfrac{4}{5}\)
\(\dfrac{1}{7}=\dfrac{1\times5}{7\times5}=\dfrac{5}{35}\)
\(\dfrac{4}{5}=\dfrac{4\times7}{5\times7}=\dfrac{28}{35}\)
Vậy \(\dfrac{5}{35}< \dfrac{28}{35}hay\dfrac{1}{7}< \dfrac{4}{5}\)
a.\(\dfrac{17}{60}=\dfrac{17}{60}\)
\(\dfrac{4}{5}=\dfrac{4\times12}{5\times12}=\dfrac{48}{60}\)
b.\(\dfrac{5}{6}=\dfrac{5\times4}{6\times4}=\dfrac{20}{24}\)
\(\dfrac{9}{8}=\dfrac{9\times3}{8\times3}=\dfrac{27}{24}\)
c.\(\dfrac{1}{2}=\dfrac{1\times6}{2\times6}=\dfrac{6}{12}\)
\(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)
\(\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)
d.\(\dfrac{1}{2}=\dfrac{1\times6}{2\times6}=\dfrac{6}{12}\)
\(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)
\(\dfrac{7}{12}=\dfrac{7}{12}\)
a)
\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)
Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)
Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).
b)
\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)
Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)
Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).
c)
\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)
Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)
Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).
d)
\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)
Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).
`MSC:36`
`5/12=(5xx3)/(12xx3)=15/36`
`4/9=(4xx4)/(9xx4)=16/36`
`-> 5/12 < 4/9`
`----`
`MSC:60`
`7/60` giữ nguyên
`1/5=(1xx12)/(5xx12)=12/60`
`->7/60<1/5`