Question

[윤아]

So Sánh: B = \(\frac{^{3^{10}.11+3^{10}.5}}{3^9.2^4}\) và C= \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

Answer 1

[nguyen thuy linh]

Ta có:

B=\(\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\)  = \(\frac{3^{10}.16}{3^9.2^4}\)= \(\frac{3^9.3.16}{3^9.16}\)= 3

C=\(\frac{2^{10}.\left(13+65\right)}{2^8.104}\) =\(\frac{2^{10}.78}{2^8.104}\)  = \(\frac{2^8.2^2.78}{2^8.104}\)=  \(\frac{4.78}{104}\)  = \(\frac{4.78}{4.26}\)=\(\frac{78}{26}\)=3

=>B=C