Question

[Mycute]

So sánh A và B

\(A=\frac{100^{2015}+1}{100^{2014}+1}\)

\(B=\frac{100^{2016}+1}{100^{2015}+1}\)

Gấp nha!

Answer 1

[Đỗ Hữu Hòa]

Ta có:

B>\(\frac{100^{2016}+1+99}{100^{2015}+1+99}\)=\(\frac{100^{2016}+100}{100^{2015}+100}\)=\(\frac{100\left(100^{2016}+1\right)}{100\left(100^{2015}+1\right)}\)=\(\frac{100^{2015}+1}{100^{2014}+1}\)=A

Vậy B>A