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1919/1212 + 51515151/36363636 = 3.
Ai tk cho mình mình tk lại.
\(\frac{1919}{1212}+\frac{515151}{363636}\)
\(=\frac{19}{12}+\frac{17}{12}\)
\(=\frac{36}{12}\)
\(=3\)
\(\frac{1919}{1212}\)+\(\frac{51515151}{36363636}\)
=\(\frac{1919:101}{1212:101}\)+\(\frac{51515151:1010101}{36363636:1010101}\)
=19/12+51/36
=3
\(\frac{1919}{1212}\)+ \(\frac{51515151}{36363636}\)= \(\frac{1919:101}{1212:101}\)+ \(\frac{51515151:1010101}{36363636:1010101}\)= \(\frac{19}{12}\)+ \(\frac{51}{36}\)= \(3\)
rút gọn PS thì ta có
B = 4/5 + 12/35 + 4/21 + 4/33
B = 16/11
\(B=\frac{4}{5}+\frac{12}{35}+\frac{4}{21}+\frac{4}{33}\)
\(B=\left(\frac{28}{35}+\frac{12}{35}\right)+\left(\frac{44}{231}+\frac{28}{231}\right)\)
\(B=\frac{8}{7}+\frac{24}{77}\)
\(B=\frac{88}{77}+\frac{24}{77}=\frac{112}{77}=\frac{16}{11}\)
Ta có: \(A=\frac{432143214321}{999999999999}=\frac{4321\times100010001}{9999\times100010001}=\frac{4321}{9999}< \frac{1}{2}\)
\(B=\frac{1212+1212+1212+1212}{1919+1919+1919+1919}=\frac{1212\times4}{1919\times4}=\frac{1212}{1919}=\frac{12\times101}{19\times101}=\frac{12}{19}>\frac{1}{2}\)
Do:\(A< \frac{1}{2}< B\Rightarrow A< B\)