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a)\(-\frac{6}{7}< \frac{3}{7}< \frac{18}{7}\)
b) \(\frac{17}{35}>\frac{17}{53}\)
c) \(\frac{17}{35}< \frac{17}{-35}\)
d) Ta có : \(\frac{12}{7}=\frac{60}{35}\)
\(\frac{17}{5}=\frac{85}{35}\)
\(\Rightarrow\frac{12}{7}< \frac{17}{5}\)
a)\(\frac{3}{7}\)>\(\frac{18}{7}\)>\(\frac{-6}{7}\)
b)\(\frac{17}{35}\)>\(\frac{17}{53}\)
c)\(\frac{17}{35}\)<\(\frac{17}{-35}\)
d)\(\frac{12}{7}\)<\(\frac{17}{5}\)
hok tốt
a ) \(-\frac{6}{7}< \frac{3}{7}< \frac{18}{7}\)
b ) \(\frac{17}{35}>\frac{17}{-35}\)
c ) \(\frac{17}{35}>\frac{17}{53}\)
d ) \(\frac{12}{7}< \frac{17}{5}\)
b/ Ta có: 291>290=(25)18=3218>2518=(52)18=536>535 => 291>535
c/ Ta có: 2225=(23)75=875
3150=(32)75=975
Vì 875<975 nên 2225<3150
a)Ta có: 2^27=(2^3)^9=8^9
3^18=(3^2)^9=9^9
Vì 8^9 <9^9
2^27<3^18
d)Ta có :27^7=(3^3)^7=3^21
9^12=(3^2)^12=3^24
Vì 3^21<3^24
27^7<9^12
\(\left\{{}\begin{matrix}a=\dfrac{35}{49}=\dfrac{5}{7}\\b=\sqrt{\dfrac{5^2}{7^2}}=\dfrac{5}{7}\\c=\dfrac{\sqrt{5^2}+\sqrt{35^2}}{\sqrt{7^2}+\sqrt{49^2}}=\dfrac{5+35}{7+49}=\dfrac{5}{7}\\d=\dfrac{\sqrt{5^2}-\sqrt{35^2}}{\sqrt{7^2}-\sqrt{49^2}}=\dfrac{5-35}{7-49}=\dfrac{5}{7}\end{matrix}\right.\)
\(\Rightarrow a=b=c=d=\dfrac{5}{7}\)
\(a=\dfrac{35}{49};b=\dfrac{5}{7}\\ c,=\dfrac{5+35}{7+49}=\dfrac{12}{14}=\dfrac{6}{7}\\ d,=\dfrac{5-35}{7-49}\)
Áp dụng t/c dtsbn:
\(\dfrac{5}{7}=\dfrac{35}{49}=\dfrac{5+35}{7+49}=\dfrac{5-35}{7-49}\) hay \(a=b=c=d\)
Ta có:\(-\dfrac{35}{12}< -1< -\dfrac{2}{7}\)
ghê