Question

[Nguyễn Linh]

S= \(\frac{1}{50}+\frac{1}{51}+\frac{1}{52}+...+\frac{1}{98}+\frac{1}{99}\). So sánh S với \(\frac{1}{2}\)

Answer 1

[Nguyễn Ngọc Quý]

S = \(\frac{1}{50}+\frac{1}{51}+...+\frac{1}{99}>\frac{1}{100}+\frac{1}{100}+\frac{1}{100}+...+\frac{1}{100}=\frac{1}{100}.50=\frac{1}{2}\)

Kết luận vậy S > 1/2

Answer 2

[ae CLAN]

S=1/2