Question

[trí kiên]

rút gọn phân thức :

a) x^2+2x+1/x^2+x

b) -x^2+5x+6/x^2+4x+4

Answer 1

[Nguyễn Hoàng Minh]

\(a,=\dfrac{\left(x+1\right)^2}{x\left(x+1\right)}=\dfrac{x+1}{x}\\ b,=\dfrac{-\left(x^2-5x-6\right)}{\left(x+2\right)^2}=\dfrac{-\left(x+1\right)\left(x-6\right)}{\left(x+2\right)^2}\)