Question

[nguyễn hà phương]

rut gon phan thuc:

a, \(\frac{10x}{5x^2}\)

b,\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}\)

Answer 1

[Phạm Lan Hương]

a/\(\frac{10x}{5x^2}=\frac{2}{x}\)

b/\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}=\frac{\left(x-y\right)\left(x+y\right)}{x\left(x+y\right)}=\frac{x-y}{x}\)