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\(\dfrac{-33}{88}=\dfrac{-3}{8};11.8-\dfrac{11.3}{17-6}=88-\dfrac{33}{11}=88-3=85.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{11\cdot8-11\cdot3}{17-6}\)
\(=\dfrac{11\cdot\left(8-3\right)}{11}=5\)
b) \(\dfrac{24-12\cdot13}{12+4\cdot9}\)
\(=\dfrac{12\cdot\left(2-13\right)}{12\left(1+3\right)}=\dfrac{-11}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
RÚT GỌN VỀ PHÂN SỐ TỐI GIẢN
câu a) \(\dfrac{-147}{252}=\dfrac{-7}{12}\)
câu b) \(\dfrac{765}{900}=\dfrac{17}{20}\)
câu c) \(\dfrac{11\cdot3-11\cdot8}{17-6}=\dfrac{-5}{1}\)
câu d) \(\dfrac{3^5\times2^4}{8\times3^6}=\dfrac{2}{3}\)
câu e) \(\dfrac{84\cdot45}{49\cdot54}=\dfrac{10}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3.7.8.13}{14\cdot15\cdot26}=\frac{3\cdot7\cdot8\cdot13}{2\cdot7\cdot3\cdot5\cdot2\cdot13}=\frac{8}{5\cdot2\cdot2}=\frac{8}{20}=\frac{2}{5}\)
\(\frac{3.7.8.13}{14.15.26}=\frac{3.7.2^3.13}{2.7.3.5.13.2}=\frac{1.7.2.1}{1.1.1.5.1.1}=\frac{14}{5}\)
\(\frac{11.8-11.3}{17-6}=\frac{11.\left(8-3\right)}{11}=\frac{11.5}{11}=\frac{1.5}{1}=\frac{5}{1}=5\)
\(\frac{-17.13+17.2}{11.2-11.9}=\frac{-17.13+\left(-17\right).2}{11.\left(2-9\right)}=\frac{-17.\left(-13+2\right)}{11.\left(-7\right)}=\frac{-17.\left(-11\right)}{11.\left(-7\right)}=\frac{-17.\left(-1\right)}{-1.\left(-7\right)}=\frac{17}{7}\)
\(\frac{7}{9.10^2-2.10^2}=\frac{7}{100\left(9-2\right)}=\frac{7}{100.7}=\frac{7}{700}=\frac{1}{100}\)
mình làm được tới đó thôi, hihi.
![](https://rs.olm.vn/images/avt/0.png?1311)
27/-72 = 27:(-9)/-72:(-9) = -3/8
-2020:(-2020)/-4040:(-2020) = 1/2
11.8-11.3/17-6= 11.(8-3)/11= 11.5/11= 5
20-12.30/30+30.10 = 20-360/30+300 = -340/330 = -34/33 = -1 1/33
\(\text{#TuanNam}\)
`27/-72=-27/72=`\(\dfrac{-27\div9}{72\div9}=\dfrac{-3}{8}\)
`-2020/-4040=202/404=`\(\dfrac{202\div202}{404\div202}=\dfrac{1}{2}\)
`11*8-`\(\dfrac{11\cdot3}{17-6}=88-3=85\)
\(\dfrac{20-12\cdot20}{30+30\cdot10}=\dfrac{20\cdot\left(1-12\right)}{30\cdot\left(1+10\right)}=\dfrac{20\cdot-11}{30\cdot11}=-\dfrac{2}{3}\)