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`a) (2^5 .3^2)/(2^3 .3)`
`= (2^2 .3)/1`
`= 4.3`
`=12`
`b) (5^3 .6)/(5.2^2)`
`= (5^3 .2.3)/(5.2^2)`
`= (5^2 .3)/2`
`= 75/2`
`c) (8.5^2-8.4^2)/(2^2 .3^2)`
`= (8.(5^2-4^2))/(4.9)`
`= (8.9)/(4.9)`
`= (2.4.9)/(4.9)`
`=2`
`d) (7^4 .2^2+7^4 .3)/(49.26)`
`= (7^4.(2^2+3))/(7^2 .26)`
`= (7^4 .7)/(7^2 .26)`
`= (7^5)/(7^2. 26)`
`= (7^3)/26`
`= 343/26`
b: \(N=3x-2y+5x-y-7y+2x=10x-10y=10\cdot\left(x-y\right)=0\)
\(a,M=12-x+x-73+96+x-23=x+12\\ M=101+12=113\\ b,N=3x-2y+5x-y-7y+2x=10x-10y\\ N=10\cdot2021-10\cdot2021=0\)
a,M=2^0-2^1+2^2-2^3+2^4-2^5+.....+2^2012
2M=2^1-2^2+2^3-2^4+2^5-2^5+......-2^2012+2^2013
3M=2^0+2^2013
M=(2^0+2^2013)÷3
Vậy.......
b,N=3-3^2+3^3-3^4+3^5-3^6+.....+3^2011-3^2012
3N=3^2-3^3+3^4-3^5+3^6-3^7+......+3^2012-3^2013
4N=3-3^2013
N=(3-3^2013)÷4
Vậy........
K tao nhé ko lên lớp tao đánh m😈😈😈
rút gọn các biểu thức
a.x+8-x-2
= (x-x) + (8 - 2)
= 0 + 6 = 6
b.a-m+7-8+m
= a - (m-m) + (7-8)
= a -0 - 1 = a-1
a.x+8-x-2
= (x-x) + (8 - 2)
= 0 + 6 = 6
b.a-m+7-8+m
= a - (m-m) + (7-8)
= a -0 - 1 = a-1
Giải:
a,\(\dfrac{2^5.3^2}{2^3.3}=2^2.3=12\)
b, \(\dfrac{5^3.6}{5.2^2}=\dfrac{5^3.2.3}{5.2^2}=\dfrac{5^2.3}{2}=37,5\)
c, \(\dfrac{8.5^2-8.4^2}{2^2.3^2}=\dfrac{8.\left(5^2-4^2\right)}{2^2.3^2}=\dfrac{8.9}{4.9}=2\)
d, \(\dfrac{7^4.2^2+7^4.3}{49.26}=\dfrac{7^4.\left(2^2+3\right)}{7^2.26}=\dfrac{7^4.7}{7^2.26}=\dfrac{343}{26}\)
Have a nice day!
a/ \(\dfrac{2^5\cdot3^2}{2^3\cdot3}=2^2\cdot3=12\)
b/ \(\dfrac{5^3\cdot6}{5\cdot2^2}=\dfrac{5^2\cdot6}{2^2}=\dfrac{150}{4}=37.5\)
c/ \(\dfrac{8\cdot5^2-8\cdot4^2}{2^2\cdot3^2}=\dfrac{200-2048}{36}=-\dfrac{1848}{36}\)