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C = \(\dfrac{1010}{1008\times8-994}\)
C = \(\dfrac{1010}{8064-994}\)
C = \(\dfrac{1010}{7070}\)
C = \(\dfrac{1}{7}\)
D = \(\dfrac{1.2.3+2.4.6+3.6.9+5.10.15}{1.3.6+2.6.12+3.9.18+5.15.30}\)
D = \(\dfrac{6+8.6+6.27+6.125}{18+18.8+18.27+18.125}\)
D = \(\dfrac{6.\left(1+8+27+125\right)}{18.\left(1+8+27+125\right)}\)
D = \(\dfrac{1}{3}\)
C = \(\frac{1010}{1008.8-994}\)
= \(\frac{1010}{1008.7+1008-994}\)
= \(\frac{1010}{1008.7+14}\)
= \(\frac{1010}{1008.7+2.7}\)
= \(\frac{1010}{7\left(1008+2\right)}=\frac{1010}{7.1010}=\frac{1}{7}\)
D = \(\frac{1.2.3+2.4.6+3.6.9+5.10.15}{1.3.6+2.6.12+3.9.18+5.15.30}\)
= \(\frac{1.2.3+2.4.6+3.6.9+5.10.15}{1.3.2.3+2.6.4.3+3.9.6.3+5.15.10.3}\)
= \(\frac{1.2.3+2.4.6+3.6.9+5.10.15}{3\left(1.2.3+2.4.6+3.6.9+5.10.15\right)}=\frac{1}{3}\)
BCNN(7,3) = 21
\(\frac{1}{7}=\frac{1.3}{7.3}=\frac{3}{21}\)
\(\frac{1}{3}=\frac{1.7}{3.7}=\frac{7}{21}\)
a)\(=\frac{1}{7}\)
b)\(=\frac{1}{3}\)
quy đồng \(\frac{1}{7}=\frac{3.1}{3.7}=\frac{3}{21}\)
\(\frac{1}{3}=\frac{7.1}{7.3}=\frac{7}{21}\)
\(\frac{3}{21}+\frac{7}{21}=\frac{9}{21}=\frac{3}{7}\)
C = \(\frac{1010}{\left(1010-2\right).8-994}\)
= \(\frac{1010}{1010.8-2.8-994}\)
=\(\frac{1010}{1010.\left(8-1\right)}\)
=\(\frac{1}{7}\)
D = \(\frac{1.2.3.\left(1+2^3+3^3+5^3\right)}{1.3.6.\left(1+2^3+3^3+5^3\right)}\)
= \(\frac{1}{3}\)
Quy đồng ta được 2 phân số là: \(\frac{3}{21};\frac{7}{21}\)
\(C=\dfrac{1010}{7710}=\dfrac{101}{771}=\dfrac{48783}{771\cdot483}\)
\(D=\dfrac{6+2\cdot4\cdot6+3\cdot6\cdot9+125\cdot6}{6\cdot3+6\cdot24+6\cdot81+6\cdot375}\)
\(=\dfrac{1+2\cdot4+3\cdot6+125}{3+24+81+375}=\dfrac{152}{483}=\dfrac{117192}{483\cdot771}\)
mà 48783<117192
nên C<D