Question

[kudo shinichi]

Q= (1/99+12/999+123/999)(1/2-1/3-1/6)

Answer 1

[VRCT_Hoàng Nhi_BGS]

Q=(1/99+12/999+123/999)x0

Q=0

Answer 2

[Nguyễn Thị Ngọc Ánh]

\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\))

\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0=0\)