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a: 9-25=7-x-(25+7)
=>7-x-25-7=-16
=>-x-25=-16
=>x+25=16
hay x=-9
b: \(10+2\left|x\right|=2\cdot\left(3^2-1\right)\)
\(\Leftrightarrow2\left|x\right|=2\cdot8-10=6\)
=>x=3 hoặc x=-3
c: -6x=18
nên x=18:(-6)=-3
\(9^{x-1}=9\)
\(9^{x-1}=9^1\)
\(x-1=1\)
\(x=1+1\)
\(x=2\)
\(\frac{6x-18}{3}+25\times2=78\)
\(\frac{6\left(x-3\right)}{3}+50=78\)
\(2\left(x-3\right)=78-50\)
\(2x-6=28\)
\(2x=28+6\)
\(2x=34\)
\(x=\frac{34}{2}\)
\(x=17\)
a) \(9^{x-1}=9\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
b) \(\left(6x-18\right):3+25.2=78\)
\(\Rightarrow3\left(2x-6\right):3+50=78\)
\(\Rightarrow2x-6=38\)
\(\Rightarrow2x=44\)
\(\Rightarrow x=22\)
Vậy \(x=22\)
b. -6x=18
=> x = 18 : (-6)
=> x = -3
c. 35-3.|x|=5.(23-4)
=> 35-3.|x|=5.(8-4)
=> 35-3.|x|=5.4
=> 35-3.|x|=20
=> 3.|x|=35-20
=> 3.|x|=15
=> |x|=5
=> x \(\in\){-5; 5}
d. => 10+2.|x|=2.(9-1)
=> 10+2.|x|=2.8
=> 10+2.|x|=16
=> 2.|x|=16-10
=> 2.|x|=6
=> |x|=3
=> x \(\in\){-3; 3}
9-25=(7-x)-(25+7)
-16=7-x-32
7-x-32=16
7-x=-16+32
7-x=16
x=16+7
x=23
B,35-3.|x|=5.(2^3-4)
35-3.x=5.(8-4)
35-3.x=5.4
35-3.x=20
3.x=35-20
3.x=15
X=15:3
x =5
C, -6x=18
-6.x=18
X=18:(-6)
X= -3
D,10+2.|x|=2.(3^2-1)
10+2.x=2.8
10+2.x=16
2.x=16-10
2.x =6
X=6:2
x=3
Ok k mk nha
a) 9 - 25 = ( 7 - x) - (25+7)
- 16 = 7-x - 32
7 - x - 32 = -16
7 - x = -16 + 32
7 - x = 16
x = 16 + 7
x = 23
b) -6x = 18
- 6 .x = 18
x = 18 : (-6)
x = -3
a. 8x+2x =25. 2 mũ 2
8x+2x=100
(8+2)x=100
10x=100
x=100:10
x=10
b.5x+2x=35
(5+2)x=35
7x=35
x=35:7
x=5
a) 8x + 2x = 25 . 22
8x + 2x = 100
( 8 + 2 )x = 100
10x = 100
x = 100 : 10
x = 10
b) 5x + 2x = 35
( 5 + 2 )x = 35
7x = 35
x = 35 : 7
x = 5
c) 5x + x = 150 : 2 + 3
5x + x = 75 + 3
5x + x = 78
( 5 + 1 )x = 78
6x = 78
x = 78 : 6
x = 13
d) 6x + x = 511 : 59 + 31
6x + x = 52 + 31
6x + x = 25 + 3
6x + x = 28
( 6 + 1 )x = 28
7x = 28
x = 28 : 7
x = 4
e) 5x + 3x = 36 : 33 . 4 + 12
5x + 3x = 33 . 4 + 12
5x + 3x = 27 . 4 + 12
5x + 3x = 108 + 12
5x + 3x = 120
( 5 + 3 )x = 120
8x = 120
x = 120 : 8
x = 15
l x - 18 l x 22018 = 22020
=> | x - 18 | x 2 2018 = 2 2018 . 2 2
=> | x - 18 | = 4
=> \(\orbr{\begin{cases}x-18=4\\x-18=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=14\end{cases}}}\)
6x - 36 = 2 3 x 32
=> 6x - 36 = 72
=> 6x = 108
=> x = 18
l x - 5 l = 8
=> \(\orbr{\begin{cases}x-5=8\\x-5=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=13\\x=-3\end{cases}}}\)
17 - x = 25
=> x = 17 - 25
=> x = - 8
198 - 2 ( 93 - x ) = 25
=> 2 ( 93 - x ) = 173
=> 93 - x = 86,5
=> x = 6,5
\(\left|x+2\right|=0\)
\(\Rightarrow x+2=0\)
\(\Rightarrow x=0-2\)
\(\Rightarrow x=-2\)
\(\left|x-5\right|=\left|-7\right|\)
\(\Rightarrow\left|x-5\right|=7\)
\(\Rightarrow\hept{\begin{cases}x-5=-7\\x-5=7\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-7+5\\x=7+5\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\x=12\end{cases}}\)
\(\Rightarrow x\in\left\{-2;12\right\}\)
\(x^2\) + 6\(x\) + 9 = 25
\(x^2\) + 6\(x\) + 9 - 25 = 0
\(x^2\) + 6\(x\) + (9 - 25) = 0
\(x^2\) + 6\(x\) - 16 = 0
\(x^2\) - 2\(x\) + 8\(x\) - 16 = 0
(\(x^2\) - 2\(x\)) + (8\(x\) - 16) = 0
\(x\)(\(x\) - 2) + 8(\(x-2\)) = 0
(\(x\) - 2)(\(x\) + 8) = 0
\(\left[{}\begin{matrix}x-2=0\\x+8=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=-8\end{matrix}\right.\)
Vậy \(x\) \(\in\) {2; - 8}
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