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\(\dfrac{1}{32}\) = 2-5
\(\dfrac{1}{8}\) = 2-3
0,5 = \(\dfrac{1}{2}\) = 2-1
0,25 = \(\dfrac{1}{4}\) = 2-2
a) \(15^8\cdot2^4\)
\(=\left(15^2\right)^4\cdot2^4\)
\(=225^4\cdot2^4\)
\(=\left(225\cdot2\right)^4\)
\(=450^4\)
b) \(27^5:32^3\)
\(=\left(3^3\right)^5:\left(2^5\right)^3\)
\(=3^{15}:2^{15}\)
\(=\left(\dfrac{3}{2}\right)^{15}\)
1=1^2 ;125=5^3 ;-125=-5^3; 27=27^1; -27= -27^1
2: 5^2 25^1
\(\frac{32\cdot2^4}{2^2\cdot\frac{1}{16}}\)
\(=\frac{2^5\cdot2^4}{\frac{4}{16}}\)
\(=\frac{2^9}{\frac{1}{4}}\)
\(=2^9\cdot4\)
\(=2^9\cdot2^2\)
\(=2^{11}\)
\(27\cdot5^3\cdot3^3\cdot32^{-1}:125=3^3\cdot5^3\cdot3^3\cdot\dfrac{1}{32}:5^3=\dfrac{3^6}{32}=\dfrac{3^6}{2^5}\)
1/4×1/16×1/32=\(\frac{1}{2^2}\)x \(\frac{1}{2^4}\)x \(\frac{1}{2^6}\)=\(\frac{1}{2^{12}}\)
Ta có :
\(\frac{1}{4}.\frac{1}{16}.\frac{1}{32}=\frac{1}{2^2}.\frac{1}{2^4}.\frac{1}{2^5}=\frac{1}{2^{11}}=\frac{1^{11}}{2^{11}}=\left(\frac{1}{2}\right)^{11}\)
Chúc bạn học tốt ~
\(\begin{array}{l}a){15^8}{.2^4} = {15^{2.4}}{.2^4} = {({15^2})^4}{.2^4}\\ = {225^4}{.2^4} = {(225.2)^4} = {450^4}\\b){27^5}:{32^3} = {({3^3})^5}:{({2^5})^3}\\ = {3^{3.5}}:{2^{5.3}} = {3^{15}}:{2^{15}} = {\left( {\frac{3}{2}} \right)^{15}}\end{array}\)
a) \(15^8\cdot2^4=3^8\cdot5^8\cdot2^4=9^4\cdot25^4\cdot2^4=\left(9\cdot25\cdot2\right)^4=450^4\)
b) \(27^5:32^3=\left(3^3\right)^5:\left(2^5\right)^3=3^{15}:2^{15}=\left(\dfrac{3}{2}\right)^{15}\)
Bài 6:
a: \(2^{27}=8^9\)
\(3^{18}=9^9\)
b: Vì \(8^9< 9^9\)
nên \(2^{27}< 3^{18}\)
\(\dfrac{1}{32}\) = 2-5