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a)A=1+2+22+...+2100
=>2A=2+22+23+...2101
=>2A-A=(2+22+23+...+2101)-(1+2+22+...+2100)
=>A=2101-1
b)B=3+32+33+...+3100
=>3B=32+33+...+3101
=>3B-B=(32+33+...+3101)-(3+32+...3100)
=>2B-B=3101-3
=>B=(3101-3):2
c)C=1+2+4+8+16+...+8192
=>C=1+2+22+23+...213
=>2C=2+22+23+...+214
=>2C-C=(2+22+...+214)-(2+22+...+213)
=>C=214-2
d)D=4+42+43+...+4n
=>4D=42+43+...+4n+1
=>4D-D=(42+43+...+4n+1)-(4+42+...+4n)
=>3D=4n+1-4
=>D=(4n+1-4):3
A=2^100-2^99-....-2^2-2-1
=>2A=2^101-2^100-....-2^3-2^2-2
=>2A-A=2^101-2^100-...-2^3-2^2-2-2^100+2^99+...+2^2+2+1
=>2A-A=2^101-2^101+1=1
vậy A=1
=> A=2100- (299+298+........+22+2+1) (3)
B
Ta có: B=299+298+..........+22+2+1 (1)
=> 2B=2100+299+..........+23+22+2 (2)
Lấy (2) - (1) ta có: 2B-B=(2100+299+...........+23+22+2)-(299+298+.............+22+2+1)
=> B= 2100-1
Thay vào (3) ta có: A=2100- (2100-1)
=> A=2100-2100+1
=> A=1
a) S=(1-2)^2+(3-4)^3+......+(99-100)^99
=(-1)^2+(-1)^3+......+(-1)^99
=1+(-1)+....+(-1)
=[1+(-1)]+[1+(-1)]+.......+[1+(-1)]
=0+0+.....+0=0
1^2-2^2+3^2-4^2+.......+99^2-100^2
=(1+2)(-1)+(3+4)(-1)+......+(99+100)(-1)
=(-1)(1+2+3+4+......+99+100)=(-1).101.100:2=-5050
A=12+22+32+...+992+1002
A=1+2 (1+1)+3.(2+1)+...+99.(98+1)+100.(99+1)
A=1+2.1+2+3.2+3+...+99.98+99+100.99+100
A=(1.2+2.3+3.4+...+98.99+99.100)+(1+2+3+4+...+99+100)
A=333300+5050
A=338050
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