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\(\dfrac{55}{11}\cdot6+\dfrac{55}{16}\cdot21+\dfrac{55}{21}\cdot26+\dfrac{55}{26}\cdot31+\dfrac{55}{31}\cdot36+\dfrac{55}{36}\cdot41=30+\dfrac{1155}{16}+\dfrac{1430}{21}+\dfrac{1705}{26}+\dfrac{1980}{31}+\dfrac{2255}{36}=\dfrac{12186720}{406224}+\dfrac{29324295}{406224}+\dfrac{27661920}{406224}+\dfrac{26638920}{406224}+\dfrac{25945920}{406224}+\dfrac{25445420}{406224}=\dfrac{147203195}{406224}\)
a) \(S4=\frac{3}{50}+\frac{3}{150}+\frac{3}{300}+...+\frac{3}{9500}\)
\(S4=\frac{3}{5.10}+\frac{3}{10.15}+\frac{3}{15.20}+...+\frac{3}{95.100}\)
\(S4=\frac{3}{5}\left(\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{95}-\frac{1}{100}\right)\)
\(S4=\frac{3}{5}\left(\frac{1}{5}-\frac{1}{100}\right)\)
\(S4=\frac{3}{5}.\frac{19}{100}\)
\(S4=\frac{57}{500}\Rightarrow S=\frac{57}{500}:4=\frac{57}{2000}\)
b) \(S5=\frac{55}{11.16}+\frac{55}{16.21}+...+\frac{55}{36.41}\)
\(S5=\frac{55}{5}.\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{36}-\frac{1}{41}\right)\)
\(S5=11.\left(\frac{1}{11}-\frac{1}{41}\right)\)
\(S5=11.\frac{30}{451}\)
\(S5=\frac{30}{41}\Rightarrow S=\frac{30}{41}:5=\frac{6}{41}\)
A=55/11.16+55/16.21+55/21.26+55/26.31+55/31.36+55/36.41
=11.(5/11.16+5/16.21+...+5/36.41)
=11.(1/11-1/16+1/16-1/21+...+1/36-1/41)
=11.(1/11-1/41)
=11.30/451
=30/41
a) -(12+21-23)-(23-21+10)
=-12-21+23-23+21-12=-12-12=-24
b)(57-725)-(605-53)
=57-725-605+53=-1220
c)(55+45+45)-(15-55+45)
=55+45+45-15+55-45=110+45-15=140
-(12+21-23)-(23-21+10)
=-12-21+23-23+21-10
=(21-21)+(23-23)-(12+10)
=0+0-22=-22
(57-725)-(605-53)
=57-725-605+53
=(57+53)-(725+605)
=110-1330
=-1220
(55+45+45)- (15-55+45)
=55+45+45-15+55-45
=(45+55)+(55-15)+(45-45)
=100+40+0=140
a/ =15+37+52-37-17
=(15+52)-17+(37-37)
=67-17+0
=50
b/=38-42+14-25+27+15
=-4+14+27-25+15
=10+27-40
=37-40
=-3
c/=-21+32+12-32
=-21+12+32-32
=11+0
=11
d/=-12-21+23-23+21-10
=-33+0+11
=-22
e/=57-725-605+53
=-668-605+53
=-1273+53
=-1220
f/=55+45+15-15+55-45
=55+55+45-45+15-15
=110+0+0
=110
câu hỏi này ở lớp 5