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a) Ta có: \(48-3\left(x+5\right)=24\)
\(\Leftrightarrow48-3x-15-24=0\)
\(\Leftrightarrow9-3x=0\)
\(\Leftrightarrow3x=9\)
hay x=3
Vậy: x=3
b) Ta có: \(9x-2x=7^8:7^6\)
\(\Leftrightarrow7x=7^2\)
\(\Leftrightarrow x=7\)
Vậy: x=7
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Câu a,b bạn biết rồi nên mình không cần ghi ha =))
c) \(9^8:3^2=\left(3^2\right)^8:3^2=3^{16}:3^2=3^{16-2}=3^{14}\)
Chúc bạn học tốt.
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
1; 73.52.54.76:(55.78)
= (73.76).(52.54) : (55.78)
= 79.56: (55.78)
= (79:78).(56:55)
= 7.5
= 35
2; 33.a7.3.a2:(34.a6)
= (33.3).(a7.a2): (34.a6)
= 34.a9: (34.a6)
= (34:34).(a9:a6)
= a3
a) Ta có: \(48\cdot19+48\cdot115+134\cdot52\)
\(=48\cdot\left(19+115\right)+134\cdot52\)
\(=48\cdot134+52\cdot134\)
\(=134\cdot\left(48+52\right)\)
\(=134\cdot100=13400\)
b) Ta có: \(7^3\cdot2+8^4:64-5\)
\(=343\cdot2+8^2-5\)
\(=686+64-5\)
\(=745\)
c) Ta có: \(\left[5\cdot36-4\cdot\left(82-7\cdot11^2\right)\right]+11\cdot4\)
\(=\left[180-4\cdot\left(82-7\cdot121\right)\right]+44\)
\(=\left(180-328+3388\right)+44\)
\(=3284\)