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a) \(27+86-\left(29-5+84\right)\)
\(=27+86-29+5-84\)
\(=2+5-2\)
=5
b) \(39-\left(298-89\right)+299\)
\(=39-298+89+299\)
\(=129\)
Bài 3:
a: \(=-8\left(72+19-1\right)=-8\cdot90-720\)
b: \(=-27\left(1011-12-1\right)=-27\cdot998=-26946\)
c: \(=17\cdot\left[29+111\right]+29\cdot\left(-17\right)\)
\(=17\left(29+111-29\right)=17\cdot111=1887\)
d: \(=43\cdot\left(-1\right)+40=-43+40=-3\)
A = \(\dfrac{18}{26}\) + (-\(\dfrac{5}{27}\)) + (-\(\dfrac{22}{86}\)) + \(\dfrac{12}{39}\) - \(\dfrac{32}{43}\)
A = \(\dfrac{9}{13}\) - \(\dfrac{5}{27}\) - \(\dfrac{11}{43}\) + \(\dfrac{4}{13}\) - \(\dfrac{32}{43}\)
A = (\(\dfrac{9}{13}\) + \(\dfrac{4}{13}\)) - (\(\dfrac{11}{43}\) + \(\dfrac{32}{43}\)) - \(\dfrac{5}{27}\)
A = \(\dfrac{13}{13}\) - \(\dfrac{43}{43}\) - \(\dfrac{5}{27}\)
A = 1 - 1 - \(\dfrac{5}{27}\)
A = 0 - \(\dfrac{5}{27}\)
A = - \(\dfrac{5}{27}\)
A = 18/26 + -5/27 + -22/86 + 12/39 + -32/43
A = 9/13 + -5/27 + -11/43 + 4/13 + -32/43
A = -5/27 + ( 9/13 + 4/13 ) + ( -11/43 + -32/43 )
A = -5/27 + 1 + ( -1)
A = -5/27 + 0
A = 0
B = -10/12 + 8/15 + -19/56 + 3/-18 + 28/60
B = -5/6 + 8/15 + -19/56 + -1/6 + 7/15
B = -19/56 + ( -5/6 + -1/6 ) + ( 8/15 + 7/15 )
B = -19/56 + ( -1 ) + 1
B = -19/56 + 0
B = 0
Ta có:
\(A=\left(86-a\right)-\left(b-114\right)\)
\(=86-a-b+114\)
\(=\left(86+114\right)-\left(a+b\right)\)
\(=200-\left(a+b\right)\)
Thay \(a=39;b=161\) vào \(A\), ta được:
\(A=200-\left(39+161\right)\)
\(=200-200\)
\(=0\)
Vậy \(A=0\) tại \(a=39;b=161\).
A = (86 - a) - (b - 114)
= 86 - a - b + 114
= (86 + 114) - (a + b)
= 200 - (a + b)
Thay a = 39; b = 161 vào A, ta được:
A = 200 - (39 + 161)
= 200 - 200
= 0
Tính giá trị của biểu thức:
a) (27 + 86) - (29 - 5 + 84);
= 27 + 86 – 29 + 5 - 84
= 5
b) 39 - (298 - 89) + 299.
= 39 – 298 + 89 + 299
= 129
) (27 + 86) - (29 - 5 + 84)
= 27 + 86 - 29 + 5 - 84
= (27 – 29) + (86 – 84) + 5
= (- 2) + 2 + 5
= 0 + 5
= 5
b) 39 - (298 - 89) + 299
= 39 - 298 + 89 + 299
= (39 + 89) + (299 – 298)
= 39 + 89 + 1
= 39 + (89 + 1)
= 39 + 90
= 129