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a) Cách 1 : (3/4 + 1/2) x 5/7
= 5/4 x 5/7
= 25/28
Cách 2 : (3/4 + 1/2) x 5/7
= 3/4 x 5/7 + 1/2 x 5/7
= 15/28 + 5/14
= 25/28
b) Cách 1 : 5/7 x 13/21 + 2/7 x 13/21
= 65/147 + 26/147
= 13/21
Cách 2 : 5/7 x 13/21 + 2/7 x 13/21
= (5/7 + 2/7) x 13/21
= 1 x 13/21
= 13/21
câu c tự làm
35 x 20 x 5 8 x 9 x 125 25 x 7 x 4 72:(8x3)
= 35 x ( 20 x5 ) = ( 8x125) x 9 = (25x4)x7 = 72: 24
= 35 x 100 = 1 000 x 9 = 100x7 = 3
= 3 500 = 9 000 =700
(36x7):4
=36: 4 x 7
= 9 x7
= 63
35 x 20 x 5 = 35\(\times\)(20 \(\times\)5)= 35 \(\times\)100=3500
8 \(\times\)9 \(\times\) 125 =(8\(\times\) 125)\(\times\)9=1000\(\times\)9=9000
25 \(\times\)7\(\times\)4=(25 \(\times\)4)\(\times\)7=100\(\times\)7=700
72 : (8\(\times\)3)=72 : 8 x 3 =(72:8) x 3=9 x 3=27
(36 x 7) : 4 =36 x 7 : 4 =7 x (36 :4)=7 x 9=63
a)1+2+3+4+5+6+7+8+9
=(1+9)+(2+8)+(3+7)+(4+6)+5
=10+10+10+10+5
=10x4+5=45
b)8x3+8x7
=8x(3+7)
=8x10=80
c)8x172-8x72
=8x(172-72)
=8x100=800
a. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 +9
= (1 + 9) + (2 + 8) + (3 + 7) + ( 4 + 6) + 5
= 10 + 10 + 10 + 10 + 5
= 45
c2
6/11 x 3/7+ 5/11 x 3/7
=18/77+15/77
=33/77 rut gon voi 11 = 3/7
C!:7/5 + 4/3 + 7/5 + 4/3
=31/15+31/15
=62/15
C2:7/5 + 4/3 + 7/5 + 4/3
=7/5+4/3
=62/15
C!:7/5 + 4/3 + 7/5 + 4/3
=31/15+31/15
=62/15
C2:7/5 + 4/3 + 7/5 + 4/3
=7/5+4/3
=62/15
a, \(\frac{7}{5}+\frac{9}{7}+\frac{6}{5}+\frac{11}{7}\)
C1: \(\frac{94}{35}+\frac{6}{5}+\frac{11}{7}=\frac{136}{35}+\frac{11}{7}=5\frac{16}{35}\)
C2: \(=\left(\frac{7}{5}+\frac{6}{5}\right)+\left(\frac{9}{7}+\frac{11}{7}\right)=\frac{13}{5}+\frac{20}{7}=5\frac{16}{35}\)
b,
C1 : \(\frac{8}{14}+\frac{2}{11}+\frac{12}{14}+\frac{31}{11}=\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\frac{58}{77}+\frac{6}{7}+\frac{31}{11}=\frac{124}{77}+\frac{31}{11}=4\frac{3}{7}\)
C2:
\(\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\left(\frac{4}{7}+\frac{6}{7}\right)+\left(\frac{2}{11}+\frac{31}{11}\right)=\frac{10}{7}+3=3\frac{10}{7}=4\frac{3}{7}\)
**** cko t nha , xin xin đó
a, ( \(\frac{7}{9}\)+ \(\frac{11}{3}\)) - \(\frac{5}{3}\)= \(\frac{40}{9}\)- \(\frac{5}{3}\)
= \(\frac{25}{9}\)
b, ( \(\frac{1}{3}\)+ \(\frac{9}{7}\)) - \(\frac{8}{7}\)= \(\frac{34}{21}\)- \(\frac{8}{7}\)
= \(\frac{10}{21}\)
Cách 1: \(\dfrac{7}{8}\times\dfrac{2}{5}+\dfrac{7}{8}\times\dfrac{3}{5}\)
\(=\dfrac{14}{20}+\dfrac{21}{40}=\dfrac{35}{40}=\dfrac{7}{8}\)
Cách 2: \(\dfrac{7}{8}\times\dfrac{2}{5}+\dfrac{7}{8}\times\dfrac{3}{5}\)
\(=\dfrac{7}{8}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{7}{8}\times\dfrac{5}{5}=\dfrac{7}{8}\)
C1. \(\dfrac{7}{20}+\dfrac{21}{20}\) = \(\dfrac{7}{8}\)
C2. \(\dfrac{7}{8}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\) = \(\dfrac{7}{8}\)