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\(a,\dfrac{7}{9}-\dfrac{2}{7}+\dfrac{2}{3}+\dfrac{4}{7}\\ =\left(\dfrac{7}{9}+\dfrac{6}{9}\right)+\left(\dfrac{4}{7}-\dfrac{2}{7}\right)\\ =\dfrac{13}{9}+\dfrac{2}{7}\\ =\dfrac{109}{63}\\ b,13,8+7-5,25+4,25\\ =\left(13,8+7\right)-\left(5,25-4,25\right)\\ =20,8-1\\ =19,8\)
a)\(\frac{7}{9}-\frac{3}{7}+\frac{2}{3}-\frac{4}{7}\)
\(=\frac{7}{9}+\frac{-3}{7}+\frac{2}{3}+\frac{-4}{7}\)
\(=\left(\frac{7}{9}+\frac{2}{3}\right)+\left(\frac{-3}{7}+\frac{-4}{7}\right)\)
\(=\frac{13}{9}-1\)
\(=\frac{4}{9}\)
b)13,8 + 7 - 5,25 + 4,25
=(13,8 + 7 + 4,25 ) - 5,25
=25,05 - 5,25
=19,8
a) 7/9 - 3/7 + 2/3 - 4/7
= 7/9 - 3/7 + 6/9 - 4/7
=( 7/9 - 6/9 ) + ( 3/7 + 4/7 )
= 1/9 + 1
=10/9
b) 13,8 + 7 - 5,25 + 4,25
=(13,8 + 7 ) - (5,25 + 4,25 )
=20,8 - 9,5
= 11,3
1.
\(a,\frac{1}{7}+\frac{3}{4}+\frac{2}{7}+\frac{4}{7}=\frac{1}{7}+\frac{2}{7}+\frac{4}{7}+\frac{3}{4}\)
\(=1+\frac{3}{4}=\frac{7}{4}.\)
\(b,\frac{4}{7}:\frac{2}{5}+\frac{3}{7}:\frac{2}{5}-\frac{7}{9}=\left(\frac{4}{7}+\frac{3}{7}\right):\frac{2}{5}-\frac{7}{9}\)
\(=1:\frac{2}{5}-\frac{7}{9}=\frac{5}{2}-\frac{7}{9}\)
\(=\frac{31}{18}.\)
a)3/4+(1/7+2/7+4/7)
=3/4+1
=7/4
b)2/5:(4/7+3/7)-7/9
=2/5:1-7/9
=2/5-7/9
=-17/45
a; \(\dfrac{7}{9}\) - \(\dfrac{3}{7}\) + \(\dfrac{2}{3}\) - \(\dfrac{4}{7}\)
= (\(\dfrac{7}{9}\) + \(\dfrac{2}{3}\)) - (\(\dfrac{3}{7}\) + \(\dfrac{4}{7}\))
= \(\dfrac{13}{9}\) - 1
= \(\dfrac{4}{9}\)
b; 13,8 + 7 - 5,25 + 4,25
= (13,8 + 7) - (5,25 - 4,25)
= 20,8 - 1
= 19,8