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\(\frac{5}{9}\times\frac{8}{17}+\frac{4}{9}\times\frac{8}{17}\)
\(=\left(\frac{5}{9}+\frac{4}{9}\right)\times\frac{8}{17}\)
\(=1\times\frac{8}{17}\)
\(=\frac{8}{17}\)
bài 1
\(\frac{2}{5}+x=4\) , \(\frac{8}{7}:x=\frac{4}{5}\)
\(\Rightarrow\)\(x=4-\frac{2}{5}\) , \(\Rightarrow\)\(x=\frac{8}{7}:\frac{4}{5}\)
\(\Rightarrow\)\(x=\frac{18}{5}\) , \(\Rightarrow\) \(x=\frac{10}{7}\)
tính cách thuận tiện là dấu = là x vì viết nhầm
\(\frac{5}{6}:\frac{8}{9}-\frac{3}{4}:\frac{8}{9}\)
\(=\left(\frac{5}{6}-\frac{3}{4}\right):\frac{8}{9}\)
\(=\frac{1}{12}:\frac{8}{9}\)
\(=\frac{1}{12}\times\frac{9}{8}\)
\(=\frac{3}{32}\)
(\(\frac{5}{6}\)-\(\frac{3}{4}\)) : \(\frac{8}{9}\)
=\(\frac{1}{12}\): \(\frac{8}{9}\)
=\(\frac{3}{32}\)
k nhé, sau đó kb lun!
a. \(\dfrac{17}{13}-\dfrac{14}{23}+\dfrac{9}{13}-\dfrac{9}{23}=\left(\dfrac{17}{13}+\dfrac{9}{13}\right)-\left(\dfrac{14}{23}+\dfrac{9}{23}\right)=\dfrac{26}{13}-\dfrac{23}{23}=2-1=1\)
b.\(\dfrac{49}{5}-\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{32}-\dfrac{1}{16}-\dfrac{1}{32}=\dfrac{49}{5}-\left(1-\dfrac{1}{32}\right)=\dfrac{44}{5}+\dfrac{1}{32}=\dfrac{1413}{160}\)
a) 3/7+5/2+4/7
=(3/7+4/7)+5/2
=1+5/2
=7/2
b)6/8+4/5+1/4
=(6/8+1/4)+4/5
=1+4/5
=9/5
đến đó thôi mệt quá
a; \(\dfrac{3}{7}\) + \(\dfrac{5}{2}\) + \(\dfrac{4}{7}\)
= (\(\dfrac{3}{7}+\dfrac{4}{7}\)) + \(\dfrac{5}{2}\)
= 1 + \(\dfrac{5}{2}\)
= \(\dfrac{2}{2}+\dfrac{5}{2}\)
= \(\dfrac{7}{2}\)
b; \(\dfrac{6}{8}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\)
= \(\dfrac{1}{4}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)) + \(\dfrac{4}{5}\)
= \(\dfrac{2}{4}\) + \(\dfrac{4}{5}\)
= \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\)
= \(\dfrac{5}{10}\) + \(\dfrac{8}{10}\)
= \(\dfrac{13}{10}\)
4/5 : 2/9 x 2/9 : 4/5
= 4/5 x 9/2 x 2/9 x 5/4
= ( 4/5 x 5/4 ) x ( 9/2 x 2/9 )
= 1x1
= 1
\(\frac{4}{5}:\frac{2}{9}\times\frac{2}{9}:\frac{4}{5}\)
\(=\frac{4}{5}\times\frac{9}{2}\times\frac{2}{9}\times\frac{5}{4}\)
\(=\left(\frac{4}{5}\times\frac{5}{4}\right)\times\left(\frac{2}{9}\times\frac{9}{2}\right)\)
\(=1\times1\)
\(=1\)
=\(\frac{3}{4}\times\left(\frac{8}{9}+\frac{2}{3}\right)\)
\(=\frac{3}{4}\times\frac{14}{9}\)
\(=\frac{7}{6}\)
