Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
`@` `\text {Ans}`
`\downarrow`
`a)`
\(2^{13}\cdot4^5\cdot8^2\)
`=`\(2^{13}\cdot\left(2^2\right)^5\cdot\left(2^3\right)^2\)
`=`\(2^{13}\cdot2^{10}\cdot2^6\)
`=`\(2^{29}\)
`b)`
\(100^6. 1000^4. 1000000\)\(33\)
`=`\(10^{12}\cdot10^{12}\cdot10^{198}=10^{222}\)
`c)`
\(24^5. 6^5. 8^8\)
`=`\(2^{15}\cdot3^5\cdot2^5\cdot3^5\cdot2^{24}\)
`=`\(2^{15+5+24}\cdot3^{5+5}\)
`=`\(2^{44}\cdot3^{10}\)
a, \(2^{13}\cdot4^5\cdot8^2=2^{13}\cdot2^{10}\cdot2^6=2^{19}.\)
b, \(100^6\cdot1000^4\cdot1000000^{33}=10^{12}\cdot10^{12}\cdot10^{198}=10^{222}.\)
c, \(24^5\cdot6^5\cdot8^8=2^{15}\cdot3^5\cdot2^5\cdot3^5\cdot2^{24}=2^{44}\cdot3^{10}.\)
Ta có:
a) \(A=2000\cdot2009=2000\cdot\left(2005+4\right)=2000\cdot2005+2000\cdot4\)
\(B=2004\cdot2005=\left(2000+4\right)\cdot2005=2000\cdot2005+2005\cdot4\)
Do \(2000< 2005\)
\(\Rightarrow2000\cdot4< 2005\cdot4\)
\(\Rightarrow2000\cdot2005+2000\cdot4< 2000\cdot2005+2005\cdot4\)
Vậy A < B
b) \(A=3004^2=\left(3000+4\right)\cdot3004=3000\cdot3004+3004\cdot4\)
\(B=3000\cdot3008=3000\cdot\left(3004+4\right)=3000\cdot3004+3000\cdot4\)
Do \(3004>3000\)
\(\Rightarrow3004\cdot4>3000\cdot4\)
\(\Rightarrow3000\cdot3004+3004\cdot4>3000\cdot3004+3000\cdot4\)
Vậy A > B
Bỏ dấu ngoặc rồi tính:
a) (123 - 27)+ (27+ 13-123) -= 123 - 27 + 27 + 13 - 123 = 13
b) (175 + 25 + 13)-(-15 + 175 + 25) = 175 + 25 + 13 + 15 - 175 - 25 = 28
c) (2012 - 119 + 29) - (-119 + 29) = 2012 - 119 + 29 + 119 - 29 = 20122
d) -(55 - 80 + 91) - (2012 + 80 - 91) = - 55 + 80 - 91 - 2012 - 80 + 91 = - 2067
e) 123 + [54 + (-123) + 46] = 123 + 54 - 123 + 46 = 100
f) - 64 + [(-110 + 64 + 71] = -64 -110 +64 + 71 = -39
a ) x = 1 9 + 5 7 = 52 63 b ) x = 2 15 − 3 10 = − 1 6
c ) x = 2 45 − 1 9 = − 1 15 ; d ) x = − 3 7 − 4 5 − − 2 3 = − 59 105
Đáp án B