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Bài 1 :
\(S=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2010}-\frac{1}{2011}\)
\(S=\frac{1}{1}-\frac{1}{2011}=\frac{2010}{2011}\)
Bài 2 :
\(S=\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}+\frac{1}{16}-\frac{1}{19}+...+\frac{1}{58}-\frac{1}{61}\)
\(S=\frac{1}{10}-\frac{1}{61}=\frac{51}{610}\)
Bài 3 :
\(3S=\frac{3}{4\times7}+\frac{3}{7\times11}+...+\frac{3}{19\times22}\)
\(3S=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{19}-\frac{1}{22}\)
\(3S=\frac{1}{4}-\frac{1}{22}\)
\(S=\frac{18}{88}\div3=\frac{6}{88}\)
=\(2-\frac{2}{3}+\frac{2}{3}-\frac{2}{5}+\frac{2}{5}-\frac{2}{7}+....+\frac{2}{11}-\frac{2}{13}\)
=2-\(\frac{2}{13}\)=\(\frac{24}{13}\)
\(\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}+\frac{2}{9\times11}+\frac{2}{11\times13}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\)
\(=\frac{1}{3}-\frac{1}{13}\)
\(=\frac{13}{39}-\frac{3}{39}=\frac{13-3}{39}=\frac{10}{39}\)
\(2\frac{3}{13}\cdot5\frac{4}{5}\cdot7\frac{6}{7}:\frac{2}{8}=\frac{29}{13}\cdot\frac{29}{5}\cdot\frac{55}{7}:\frac{2}{8}=\frac{29\cdot29\cdot55\cdot8}{13\cdot5\cdot7\cdot2}=\frac{29\cdot29\cdot11\cdot4}{13\cdot1\cdot7\cdot1}=\frac{37004}{91}\)
Chúc bạn học tốt!^_^
A) \(\frac{1}{6}\) = 0,1666666665
B) 0,1666669167
\(\frac{1}{6}\) < \(\frac{111111}{666665}\)
Bạn lấy tử chia cho mẫu là ra
\(\frac{20}{69}\)
\(\frac{4}{3x7}\)+ \(\frac{5}{7x12}\)+ \(\frac{1}{12x13}\)+ \(\frac{7}{13x20}\)+ \(\frac{3}{20x23}\)
= \(\frac{4}{3}+5\)+\(1+7+\frac{3}{13}\)
=\(4+5+1+7+\frac{1}{13}\)
=\(17+\frac{1}{13}\)
=\(\frac{17}{1}+\frac{1}{13}=\frac{221+1}{13}=\frac{222}{13}\)