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Ta có:
\(\left(\frac{3}{5}-x\right).\left(\frac{2}{5}-x\right)>0\)
\(\Rightarrow\frac{3}{5}-x>0\)và \(\frac{2}{5}-x>0\)
\(\Rightarrow x>\frac{3}{5}\)và \(x>\frac{2}{5}\)
MÌNH NGHĨ VẬY, NHỚ KICK ĐÚNG CHO MÌNH NHA.......( ^ _ ^ )
\(\left(\frac{3}{5}-x\right)\left(\frac{2}{5}-x\right)>0\)
\(\Rightarrow\hept{\begin{cases}\orbr{\begin{cases}\frac{3}{5}-x>0\\\frac{2}{5}-x>0\end{cases}}\\\orbr{\begin{cases}\frac{3}{5}-x< 0\\\frac{3}{5}-x< 0\end{cases}}\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}\orbr{\begin{cases}x< \frac{3}{5}\\x< \frac{2}{5}\end{cases}}\\\orbr{\begin{cases}x>\frac{3}{5}\\x>\frac{3}{5}\end{cases}}\end{cases}}\)
\(\dfrac{0.\left(3\right)+0.\left(384615\right)+\dfrac{3}{13}x}{0.0\left(3\right)+13}=\dfrac{50}{85}\)
\(\Leftrightarrow\dfrac{\dfrac{28}{39}+\dfrac{3}{13}x}{\dfrac{391}{30}}=\dfrac{10}{17}\)
\(\Leftrightarrow x\cdot\dfrac{3}{13}+\dfrac{28}{39}=\dfrac{23}{3}\)
\(\Leftrightarrow x\cdot\dfrac{3}{13}=\dfrac{271}{39}\)
\(\Leftrightarrow x=\dfrac{271}{9}\)
\(B=\left(0,75-0,6+\frac{3}{7}+\frac{3}{13}\right):\left(\frac{11}{7}+\frac{11}{13}+2,75-2,2\right)\)
\(B=\left(\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}\right):\left(\frac{11}{7}+\frac{11}{13}+\frac{11}{4}-\frac{11}{5}\right)\)
\(B=3\cdot\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right):11\cdot\left(\frac{1}{7}+\frac{1}{13}+\frac{1}{4}-\frac{1}{5}\right)\)
\(B=\frac{3}{11}\)
Hi Hi!
Tìm x
\(2^{x+2}+2^{x+1}-2^x=40\)
\(\left(3-2x\right)\left(2,4+3x\right)\left(\frac{3}{2}-2x\right)=0\)
\(2^{x+2}+2^{x+1}-2^x=40\)
\(\Rightarrow2^x\left(2^2+2-1\right)=40\)
\(\Rightarrow2^x=8\)
\(\Rightarrow x=3\)
2x+2 + 2x+1 - 2x = 40
2x.22+2x.2-2x=40
2x.(4+2-1)=40
2x.5=40
2x=8
2x=23
x=3
vậy x=3
H = [0,(32) . 1,(5) - 0,(25)] . \(\frac{11}{83}\)
H = \(\left(\frac{32}{99}.\frac{15}{9}-\frac{25}{99}\right).\frac{11}{83}\)
H = \(\left(\frac{160}{297}-\frac{75}{297}\right).\frac{11}{83}\)
H = \(\frac{85}{297}.\frac{11}{83}\)
H = \(\frac{85}{2241}\)
H = ( 0 . 5 . 0).11 phần 83 (mk ko bt ghi phân số)
H = 0 . 11
H = 0
Study good
Đề bài là gì vậy bạn ??? Tính hay tìm x ?
\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}\)
\(=\frac{\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x}{\frac{1}{30}+13}=\frac{\frac{1}{3}+\frac{5+3x}{13}}{\frac{391}{30}}=\frac{\frac{13+3\left(5+3x\right)}{39}}{\frac{391}{30}}\)
\(=\frac{\frac{13+15+9x}{39}}{\frac{391}{90}}=\frac{\frac{28+9x}{39}}{\frac{391}{90}}=\frac{28+9x}{39}\cdot\frac{90}{391}\)
P/S : Sai đề trầm trọng
Tìm x nha