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\(B=\frac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)
\(B=\frac{1.2+2^2.1.2+3^21.2+4^2.1.2+5^2.1.2}{3.4+2^23.4+3^23.4+4^23.4+5^23.4}\)
\(B=\frac{2.\left(1+2^2+3^2+4^2+5^2\right)}{12\left(1+2^2+3^2+4^2+5^2\right)}\)\(\Rightarrow B=\frac{2}{12}=\frac{1}{6}\)
\(A=\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10+6\cdot12}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20+18\cdot24}\)
\(A=\frac{2\cdot3\left[1\cdot2\right]+2\cdot3\left[2\cdot4\right]+2\cdot3\left[3\cdot6\right]+2\cdot3\left[4\cdot8\right]+2\cdot3\left[5\cdot10\right]}{3\cdot4\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}\)
\(A=\frac{\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}{2\cdot3\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}=\frac{1}{2\cdot3}=\frac{1}{6}\)
a; \(\dfrac{3}{11}\) + \(\dfrac{5}{-9}\) + \(\dfrac{4}{11}\) - \(\dfrac{4}{9}\) + \(\dfrac{3}{17}\) + \(\dfrac{15}{11}\)
= (\(\dfrac{3}{11}\) + \(\dfrac{4}{11}\) + \(\dfrac{15}{11}\)) - (\(\dfrac{5}{9}\) + \(\dfrac{4}{9}\)) + \(\dfrac{3}{17}\)
= 2 - 1 + \(\dfrac{3}{17}\)
= 1 + \(\dfrac{3}{17}\)
= \(\dfrac{20}{17}\)
c; N = \(\dfrac{\dfrac{5}{7}-\dfrac{5}{9}-\dfrac{5}{11}}{\dfrac{15}{7}+\dfrac{15}{9}+\dfrac{15}{11}}\)
Phải là - \(\dfrac{5}{7}\) chỗ tử số mới đúng em nhé!
a; A = -1 + 3 - 5 + 7 - 9 + 11 - 13 + 15 - 17
A = (-1 + 11) + ( 3 - 13) + (-5 + 15) + (7 - 17) - 9
A = 10 - 10 + 10 - 10 - 9
A = (10 - 10) + (10 - 10) - 9
A = 0 + 0 - 9
A = -9
b; B = 1+2-3-4+5+6-7-8+9+10-11-12+13+14-15-16+17+18-19-20
B = (1+2-3-4) + (5+6-7-8)+(9+10-11-12)+(13+14-15-16)+(17+18-19-20)
B= -4+(-4)+(-4)+(-4)+(-4)
B= -4 . 5
B= -20
Rút gọn rồi tính:
a) \(\frac{8}{10}-\frac{12}{9}+\frac{10}{15}\)
\(=\frac{4}{5}-\frac{4}{3}+\frac{2}{3}\)
\(=\frac{12-20+10}{15}\)
\(=\frac{2}{15}\)
b) \(\left(\frac{20}{16}-\frac{15}{12}\right)\div\left(\frac{6}{8}-\frac{9}{12}\right)\)
\(=\left(\frac{5}{4}-\frac{5}{4}\right)\div\left(\frac{3}{4}-\frac{3}{4}\right)\)
\(=1\div1\)
\(=1\)
\(a,\frac{8}{10}-\frac{12}{9}+\frac{10}{15}\)
\(=\frac{4}{5}-\frac{4}{3}+\frac{2}{3}\)
\(=\frac{4}{5}-\left(\frac{4}{3}+\frac{2}{3}\right)\)
\(=\frac{4}{5}-2\)
\(=\frac{4}{5}+\frac{-10}{5}\)
\(=\frac{-6}{5}\)
\(b,\left(\frac{20}{16}-\frac{15}{12}\right):\left(\frac{6}{8}-\frac{9}{12}\right)\)
\(=\left(\frac{5}{4}-\frac{5}{4}\right):\left(\frac{3}{4}-\frac{3}{4}\right)\)
\(=0:0\)
\(=0\)