Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(10^{n+1}-6.10^n\) sorry nhầm
=\(10^n.10-6.10^n\)
=\(10^n\left(10-6\right)\)
=\(10^n.4\)
1a) \(10^{n+1}-6\cdot10^n\)
\(=10^n\cdot10-6\cdot10^n\)
= \(10^n\left(10-6\right)\)
\(=10^n\cdot4\)
b) \(2^{n+3}+2^{n+2}-2^{n+1}+2^n\)
\(=2^n\cdot2^3+2^n\cdot2^2-2^n\cdot2+2^n\)
\(=2^n\left(2^3+2^2-2+1\right)\)
\(=2^n\cdot11\)
c) \(90\cdot10^k-10^{k+2}+10^{k+1}\)
\(=90\cdot10^k-10^k\cdot10^2+10^k\cdot10\)
\(=10^k\left(90-10^2+10\right)=0\)
d) \(2,5\cdot5^{n-3}\cdot10+5^n-6\cdot5^{n-1}\)
\(=\dfrac{2,5\cdot10\cdot5^n}{5^3}+5^n-\dfrac{6\cdot5^n}{5}\)
\(=\dfrac{5^n}{5}+5^n-\dfrac{6\cdot5^n}{5}\)
\(=\dfrac{5^n+5^n\cdot5-6\cdot5^n}{5}=\dfrac{5^n\left(5-6\right)+5^n}{5}=0\)
2. \(M+\left(6x^2-4xy\right)=7x^2-8xy+y^2\)
\(M=\left(7x^2-8xy+y^2\right)-\left(6x^2-4xy\right)\)
\(M=7x^2-8xy+y^2-6x^2+4xy\)
\(M=7x^2-6x^2-8xy+4xy+y^2\)
\(M=x^2-4xy+y^2\)
\(a,3^{n+2}-3^{n+1}+6.3^n\)
\(=3^n\left(3^2-3+6\right)=3^n.12\)
\(b,\left(3.2^{n+2}+2^n+2^{n+1}\right):5\)
\(=\left[2^n\left(3.2^2+1+2\right)\right]:5\)
\(=2^n.15:5\)
\(=2^n.3\)
\(A=1+2+...+\left(n-1\right)=\frac{n\left(n-1\right)}{2}\)
\(B=\left(n-1\right)+..+2+1=\frac{\left(n-1\right)n}{2}\)
\(A+n+B=\frac{\left(n-1\right)n}{2}+n+\frac{\left(n-1\right)n}{2}=\left(n-1\right)n+n=n^2\)
n là tự nhiên \(\sqrt{n^2}=n\)
3^(n+2) - 3^(n+1)-6x3^n= 3^n x 3^2 - 3^n x 3 - 6x3^n = 3^n x (3-2+6) =3^n x 7 ( câu b tương tự )
4.10n nha bạn
10n + 1 - 6.10n
= 10n . 10 - 6.10n
= 10n . (10 - 6)
= 4.10n