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a: \(x^2+4xy+y^2\)

\(=x^2+4xy+4y^2-3y^2\)

\(=\left(x+2y-y\sqrt{3}\right)\left(x+2y+y\sqrt{3}\right)\)

31 tháng 7 2019

d) \(x^2\left(y-z\right)+y^2\left(z-x\right)+z^2\left(x-y\right)\)

\(=x^2\left(y-z\right)+y^2\left[\left(z-y\right)-\left(x-y\right)\right]+z^2\left(x-y\right)\)

\(=x^2\left(y-z\right)-y^2\left(y-z\right)-y^2\left(x-y\right)+z^2\left(x-y\right)\)

\(=\left(y-z\right)\left(x^2-y^2\right)-\left(x-y\right)\left(y^2-z^2\right)\)

\(=\left(y-z\right)\left(x-y\right)\left(x+y\right)-\left(x-y\right)\left(y-z\right)\left(y+z\right)\)

\(=\left(y-z\right)\left(x-y\right)\left(x+y-y-z\right)\)

\(=\left(y-z\right)\left(x-y\right)\left(x-z\right)\)

31 tháng 7 2019

a) \(2x^2-5xy+3y^2\)

\(=2x^2-2xy-3xy+3y^2\)

\(=2x\left(x-y\right)-3y\left(x-y\right)\)

\(=\left(2x-3y\right)\left(x-y\right)\)

4 tháng 10 2019

\(1.=5xy\left(x-2y\right)\)

\(2.=\left(5-y\right)\left(x-y\right)\)

\(3.=y\left(x-z\right)-7\left(x-z\right)=\left(y-7\right)\left(x-z\right)\)

\(5.=2x\left(3y-7z\right)-6y\left(3y-7z\right)=\left(2x-6y\right)\left(3y-7x\right)\)

\(4.=27x^2\left(y-1\right)+9x^3\left(y-1\right)=9x^2\left(3+x\right)\left(y-1\right)\)

19 tháng 10 2020

a) 5x3 - 40 = 5( x3 - 8 ) = 5( x - 2 )( x2 + 2x + 4 )

b) x2z + 4xyz + 4y2z = z( x2 + 4xy + 4y2 ) = z( x + 2y )2

c) 4x2 - y2 - 6x + 3y = ( 4x2 - y2 ) - ( 6x - 3y ) = ( 2x - y )( 2x + y ) - 3( 2x - y ) = ( 2x - y )( 2x + y - 3 )

d) x2 + 2x - 4y2 + 1 = ( x2 + 2x + 1 ) - 4y2 = ( x + 1 )2 - ( 2y )2 = ( x - 2y + 1 )( x + 2y + 1 )

e) 3x2 - 3y2 - 12x + 12y = 3( x2 - y2 - 4x + 4y ) = 3[ ( x2 - y2 ) - ( 4x - 4y ) ] = 3[ ( x - y )( x + y ) - 4( x - y ) ] = 3( x - y )( x + y - 4 )

f) x3 + 5x2 + 4x + 20 = x2( x + 5 ) + 4( x + 5 ) = ( x + 5 )( x2 + 4 )

g) x3 - x2 - 25x + 25 = x2( x - 1 ) - 25( x - 1 ) = ( x - 1 )( x2 - 25 ) = ( x - 1 )( x - 5 )( x + 5 )

19 tháng 10 2020

a) \(5x^3-40=5\left(x^3-8\right)=5\left(x-2\right)\left(x^2+2x+4\right)\)

b) \(x^2z+4xyz+4y^2z=z\left(x^2+4xy+4y^2\right)=z\left(x+2y\right)^2\)

c) \(4x^2-y^2-6x+3y=\left(4x^2-y^2\right)-\left(6x-3y\right)\)

\(=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)=\left(2x-y\right)\left(2x+y-3\right)\)

d) \(x^2+2x-4y^2+1=x^2+2x+1-4y^2\)

\(=\left(x+1\right)^2-4y^2=\left(x+2y+1\right)\left(x-2y+1\right)\)

e) \(3x^2-3y^2-12x+12y=3\left(x^2-y^2-4x+4y\right)\)

\(=3\left[\left(x^2-y^2\right)-\left(4x-4y\right)\right]=3\left[\left(x-y\right)\left(x+y\right)-4\left(x-y\right)\right]\)

\(=3\left(x-y\right)\left(x+y+4\right)\)

f) \(x^3+5x^2+4x+20=\left(x^3+5x^2\right)+\left(4x+20\right)\)

\(=x^2.\left(x+5\right)+4\left(x+5\right)=\left(x^2+4\right)\left(x+5\right)\)

g) \(x^3-x^2-25x+25=\left(x^3-x^2\right)-\left(25x-25\right)\)

\(=x^2\left(x-1\right)-25\left(x-1\right)=\left(x-1\right)\left(x^2-25\right)\)

\(=\left(x-1\right)\left(x-5\right)\left(x+5\right)\)

11 tháng 8 2015

tớ lm câu a thui nha , tại khó quá ^^

a/ \(=3x^6+3x^5+6x^4+3x^3+3x^2-7x^5-7x^4-14x^3-7x^2-7x+3x^4+3x^3+6x^2+3x+1\)

\(=3x^2\left(x^4+x^3+2x^2+x+1\right)-7x\left(x^4+x^3+2x^2+x+1\right)+3\left(x^4+x^3+2x^2+x+1\right)\)

\(=\left(3x^2-7x+3\right)\left(x^4+x^3+x^2+x^2+x+1\right)\)

\(=\left(3x^2-7x+3\right)\left[x^2\left(x^2+x+1\right)+\left(x^2+x+1\right)\right]\)

\(=\left(3x^2-7x+3\right)\left(x^2+1\right)\left(x^2+x+1\right)\)

 

31 tháng 8 2020

a. \(2a^2+5ab-3b^2-7b-2\)

\(=\left(2a^2+6ab+2a\right)-\left(ab+3b^2+b\right)-\left(2a+6b+2\right)\)

\(=2a\left(a+3b+1\right)-b\left(a+3b+1\right)-2\left(a+3b+1\right)\)

\(=\left(2a-b-2\right)\left(a+3b+1\right)\)

b. \(2x^2-7xy+x+3y^2-3y\)

\(=\left(2x^2-xy\right)-\left(6xy-3y^2\right)+\left(x-3y\right)\)

\(=x\left(2x-y\right)-3y\left(2x-y\right)+\left(x-3y\right)\)

\(=\left(x-3y\right)\left(2x-y\right)+\left(x-3y\right)\)

\(=\left(x-3y\right)\left(2x-y+1\right)\)

c. \(6x^2-xy-2y^2+3x-2y\)

\(=\left(6x^2+3xy\right)-\left(4xy-2y^2\right)+\left(3x-2y\right)\)

\(=3x\left(2x+y\right)-2y\left(2x+y\right)+\left(3x-2y\right)\)

\(=\left(3x-2y\right)\left(2x+y\right)+\left(3x-2y\right)\)

\(=\left(3x-2y\right)\left(2x+y+1\right)\)

8 tháng 10 2019

\(a,4x^4-8x^3+4x^2\)

\(=4x^2\cdot\left(x^2-2x+1\right)\)

\(=4x^2\cdot\left(x-1\right)^2\)

\(b,x^2-y^2+5\cdot\left(y-x\right)\)

\(=\left(x-y\right)\cdot\left(x+y\right)-5\cdot\left(x-y\right)\)

\(=\left(x-y\right)\cdot\left(x+y-5\right)\)

\(c,3x^2-6xy+3y^2-12z^2\)

\(=3\cdot\left(x^2-2xy+y^2-4x^2\right)\)

\(=3\cdot\left[\left(x-y\right)^2-\left(2x\right)^2\right]\)

\(=3\cdot\left(x-y-2x\right)\cdot\left(x-y+2x\right)\)

18 tháng 6 2015

a)5x2y-10xy2

=5xy(x-2y)

b,:4x(2y-z)+7y(z-2y)

=4x(2y-z)-7y(2y-z)

=(2y-z)(4x-7y)

c,:y(x-z)+7(z-x)

=y(x-z)-7(x-z)

=(x-z)(y-7)

d)36-12x+x^2​

=x2-2.x.6+62

=(x-6)2

e) (x-5)^2-16

=(x-5)2-42

=(x-5-4)(x-5+4)

=(x-9)(x-1)

f) ​8x^3+1/27

=(2x)3+(1/3)3

=(2x+1/3)(4x2+2/3.x+1/9)

19 tháng 8 2017

Cái này rất dễ mà, bạn nên tự làm