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Sửa đề: x^3+6x^2+11x+6
=x^3+x^2+5x^2+5x+6x+6
=(x+1)(x^2+5x+6)
=(x+1)(x+2)(x+3)
\(x^3-3x^2-6x+8\\ =\left(x^3+8\right)-3x\left(x+2\right)\\ =\left(x+2\right)\left(x^2-2x+4\right)-3x\left(x+2\right)\\ =\left(x+2\right)\left(x^2-5x+4\right)\\ =\left(x+2\right)\left(x-4\right)\left(x-1\right)\)
Bài 1 :
\(x^2-6x+8=x^2-2x-4x+8=x\left(x-2\right)-4\left(x-2\right)=\left(x-4\right)\left(x-2\right)\)
Bài 2 :
\(x^8+x^7+1=x^8+x^7+x^6+x^5+x^4+x^3+x^2+x+1-x^6-x^5-x^4-x^3-x^2-x\)
\(=x^6\left(x^2+x+1\right)+x^3\left(x^2+x+1\right)+x^2+x+1-x^4\left(x^2+x+1\right)-x\left(x^2+x+1\right)\)
=\(\left(x^2+x+1\right)\left(x^6+x^3+1-x^4-x\right)\)
Tick đúng nha
\(=\left(x^3-6x^2+12x-8\right)+1\\ =\left(x-2\right)^3+1\\ =\left(x-2+1\right)\left(x^2-4x+4-x+2+1\right)\\ =\left(x-1\right)\left(x^2-5x+7\right)\)
C1:
x2-6x+5=x2-x-5x+5=(x2-x)-(5x-5)=x(x-1)-5(x-1)=(x-5)(x-1)
C2:
x2-6x+5= (x2-6x+9)-4=(x-2)2-22=(x-2-2)(x-2+2)=x(x-4)
\(x^3-19x-30=\left(x-5\right)\left(x+2\right)\left(x+3\right)\)
\(x^3-19x-30\)
\(=x^3+2x^2-2x^2-4x-15x-30\)
\(=x^2\left(x+2\right)-2x\left(x+2\right)-15\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-2x-15\right)\)
\(=\left(x+2\right)\left(x-5\right)\left(x+3\right)\)
\(=x^3-x+7x+7=x\left(x-1\right)\left(x+1\right)+7\left(x+1\right)\\ =\left(x+1\right)\left(x^2-x+7\right)\)