Question

[Trang Kenny]

Phân tích đa thức thành nhân tử:

\(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\))

mn giúp em vs, em cần gấp ạ

Answer 1

[Nguyễn Phan Hoài Nam]

ta có: \(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\)

\(=\left(x+4\right)^2.\left(x^2-1\right)-\left(x^2-1\right)\)

\(=\left(x^2-1\right)\left(\left(x+4\right)^2-1\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x+4-1\right)\left(x+4+1\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x+3\right)\left(x+5\right)\)

Cho mình nhé hihi!!!

Answer 2

[Nguyễn Ngọc Mỹ]

x²(x+4)²-(x+4)²-(x²-1)

=(x+4)²  (x²-1)-(x²-1)

=(x²-1)(x²+8x+16-1)

=(x-1)(x+1)(x²+8x+15)