Question

[Nguyễn Trường Giang]

phân tích đa thức thành nhân tử 

d) \(xyz-\left(xy+yz+xz\right)+\left(x+y+z\right)-1\)

Answer 1

[Pham Van Hung]

       \(xyz-\left(xy+yz+xz\right)+\left(x+y+z\right)-1\)

\(=\left(xyz-xy-xz+x\right)-yz+y+z-1\)

\(=x\left(yz-y-z+1\right)-\left(yz-y-z+1\right)\)

\(=\left(x-1\right)\left(yz-y-z+1\right)\)

\(=\left(x-1\right)\left[y\left(z-1\right)-\left(z-1\right)\right]\)

\(=\left(x-1\right)\left(y-1\right)\left(z-1\right)\)