Câu hỏi của HOANG HA

Question

phan tich da thuc thanh nhan tu ;

$3x^2-3y^2-2\left(x-y\right)^2$

Lightning Farron · Accepted Answer

$3x^2-3y^2-2\left(x-y\right)^2$

$=3\left(x^2-y^2\right)-2\left(x-y\right)^2$

$=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)^2$

$=\left(x-y\right)\left[3\left(x+y\right)-2\left(x-y\right)\right]$

$=\left(x-y\right)\left(3x+3y-2x+2y\right)$

$=\left(x-y\right)\left(x+5y\right)$Câu trả lời: $3x^2-3y^2-2\left(x-y\right)^2$

$=3\left(x^2-y^2\right)-2\left(x-y\right)^2$

$=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)^2$

$=\left(x-y\right)\left[3\left(x+y\right)-2\left(x-y\right)\right]$

$=\left(x-y\right)\left(3x+3y-2x+2y\right)$

$=\left(x-y\right)\left(x+5y\right)$