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\(42+\frac{93}{6}+\frac{87}{12}+\frac{79}{20}+\frac{69}{30}+\frac{57}{42}\)
\(=37+\left(1+\frac{93}{6}\right)+\left(1+\frac{87}{12}\right)+\left(\frac{79}{20}+1\right)+\left(1+\frac{69}{30}\right)+\left(1+\frac{57}{42}\right)\)
\(=37+\frac{99}{6}+\frac{99}{12}+\frac{99}{20}+\frac{99}{30}+\frac{99}{42}\)
\(=37+99\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
\(=37+99\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)
\(=37+99\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(=37+99\left(\frac{1}{2}-\frac{1}{7}\right)\)
\(=37+99.\frac{5}{14}\)
\(=37+35\frac{5}{14}\)
\(=72\frac{5}{14}\)
\(\frac{29}{9}.\frac{109}{7}-\frac{29}{9}.\frac{57}{7}+\frac{29}{9}.\frac{12}{7}-\frac{29}{9}.\frac{1}{7}\)
= \(\frac{29}{9}.\left(\frac{109}{7}-\frac{57}{7}+\frac{12}{7}-\frac{1}{7}\right)\)
= \(\frac{29}{9}.\frac{63}{7}\)
=\(\frac{29}{9}.9\)
=\(\frac{29.9}{9}\)
=\(\frac{261}{9}\)
= \(29\)
hứ 7 nộp rùi giải giúp mình à
Được cập nhật 10 giờ trước (09:01)
Toán lớp 6
Chau Nguyen Van 9 giờ trước (09:40)
Báo cáo sai phạm
299 .1097 −299 .577 +299 .127 −299 .17
= 299 .(1097 −577 +127 −17 )
= 299 .637
=299 .9
=29.99
=2619
=
\(=\frac{3.\left(\frac{1}{51}-\frac{4}{57}+\frac{11}{59}\right)}{5.\left(\frac{1}{51}-\frac{4}{57}+\frac{11}{59}\right)}=\frac{3.1}{5.1}=\frac{3}{5}\)
Để A có giá trị nguyên
thì 3\(⋮\)(x-1)
mà xeZ nên x-1eZ
x-1e{3;-3}
xe{4;-2}
\(a,\frac{3}{27}+\frac{1}{4}-\frac{1}{9}=\frac{3}{27}+\frac{1}{4}-\frac{3}{27}=\frac{3}{27}-\frac{3}{27}+\frac{1}{4}=\frac{1}{4}\)
\(b,\frac{72}{25}\cdot\frac{75}{36}=\frac{72\cdot75}{25\cdot36}=\frac{2\cdot36\cdot25\cdot3}{25\cdot36}=\frac{2\cdot3}{1\cdot1}=6\)
\(c,\frac{36}{49}:\frac{48}{14}=\frac{36}{49}\cdot\frac{14}{48}=\frac{36\cdot14}{49\cdot48}=\frac{3\cdot12\cdot2\cdot7}{7\cdot7\cdot4\cdot12}=\frac{3\cdot2}{7\cdot4}=\frac{6}{28}=\frac{3}{14}\)
\(d,\frac{39}{23}:26=\frac{39}{23}\cdot\frac{1}{26}=\frac{39}{23\cdot26}=\frac{3\cdot13}{23\cdot2\cdot13}=\frac{3}{23\cdot2}=\frac{3}{46}\)
\(e,45:\frac{15}{2}=\frac{45}{1}\cdot\frac{2}{15}=\frac{45\cdot2}{15}=\frac{3\cdot15\cdot2}{15}=\frac{6}{1}=6\)
\(g,\frac{57}{8}:\frac{3}{4}-\frac{15}{7}\cdot\frac{14}{25}=\frac{57\cdot4}{8\cdot3}-\frac{15\cdot14}{7\cdot25}=\frac{3\cdot19\cdot4}{2\cdot4\cdot3}-\frac{3\cdot5\cdot2\cdot7}{7\cdot5\cdot5}\)
\(=\frac{19}{2}-\frac{3\cdot2}{5}=\frac{95}{10}-\frac{12}{10}=\frac{83}{10}\)
A=(27+53)+(46+34)+79
A=80+80+79
A=160+79
A=239
B = -377 - (98 - 277)
B=-377-98-277
B=[(-377)+277]-98
B=(-100)-98
B=-198
C= -1,7.2,3 + 1,7.(-3,7) - 1,7.3 - 0,17 : 0,1
C=1,7.(-2.3)+1,7.(-3,7)+1,7.(-3)+1,7
C=1,7.[(-2,3+(-3,7)+(-3)+1]
C=1,7.(-8)
C=-13,6
Còn mái câu kia mk hk pít lm pn th/cảm cho mk nhae
Chọn câu A