Question

[phan thi ly]

Cho x₁+x₂+.....+x₂₀₀₂=0 va x₁+x₂+x₃=x₄+x₅+x_{6=............=}x₁₉₉₉+x₂₀₀₀+x₂₀₀₁=1

Tim x₂₀₀₂

Answer 1

[Nguyễn Giang]

(x1+x2+x3)+(x4+x5+x6)+...+(x1999+x2000+x2001)+x2002=0 ⇒1+1+1+...+1+x2002=0 _____________________ (2001−1+1) 3 số 1 667+x2002=0 x2002=−667