Question

[nguyen Quynh Nhu]

A=\(\left\{n\in Z|\frac{3n+2}{2n-1}\in Z\right\}\)

xac dinh cac phan tu cua A

Answer 1

[Nguyễn Việt Lâm]

\(\frac{3n+2}{2n-1}\in Z\Rightarrow\frac{2\left(3n+2\right)}{2n-1}\in Z\Rightarrow3+\frac{7}{2n-1}\in Z\)

\(\Rightarrow\frac{7}{2n-1}\in Z\Rightarrow2n-1=Ư\left(7\right)=\left\{-1;1;7\right\}\)

\(\Rightarrow n=\left\{0;1;4\right\}\)

Vậy \(A=\left\{0;1;4\right\}\)