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\(\frac{5}{2}+\frac{5}{6}+\frac{5}{12}+...+\frac{5}{90}\)
\(=5.\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\right)\)
\(=5.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)
\(=5.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=5.\left(1-\frac{1}{10}\right)\)\
\(=5.\frac{9}{10}\)
\(=\frac{9}{2}\)
\(\dfrac{5}{2}+\dfrac{5}{6}+\dfrac{5}{12}+\dfrac{5}{20}+....+\dfrac{5}{90}\\ =5\times\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{90}\right)\\ =5\times\left(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+...+\dfrac{1}{9\times10}\right)\\ =5\times\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\\ =5\times\left(1-\dfrac{1}{10}\right)\\ =5\times\dfrac{9}{10}=\dfrac{9}{2}\)
Đặt A = 1/2 + 5/6 + 11/12 + 19/20 + ... + 89/90
A = ( 1 - 1/2 ) + ( 1 - 1/12 ) + ( 1 - 1/20 ) + ... + ( 1 - 1/90 )
A = ( 1 + 1 + 1 + ... + 1 + 1 ) - ( 1/2 + 1/6 + 1/20 + ... + 1/90
A = 9 - ( 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/9.10 )
A = 9 - ( 1 - 1/10 )
A = 9 - 9/10
A = 81/10
1/2=1-1/2
5/6=1-1/6
11/12=1-1/12
109/110=1-1/110
A=10-(1/2+1/6+...+1/110)
B=(1/2+1/6+...+1/110)=[(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/9-1/10)+(1/10+1/11)
B=1+1/11
A=10-(1+1/11)=10+1/11
1/2 + 5/6 +11/12 +...+ 89/90 + 109/110 + 10/11
= (1 - 1/2) + ( 1 - 1/6) + (1 - 1/12) + (1 - 1/20) +( 1 - 1/30) +... + (1 - 1/90) + (1- 1/110) + 10/11
= 1 x 10 –(1/2 + 1/6 + 1/12 + 1/20 +……..+ 1/90 + 1/110) + 10/11
= 10 – (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 +……+ 1/9 - 1/10 + 1/10 - 1/11 ) + 10/11
= 10 – (1 - 1/11) + 10/11
= 10 - 10/11 + 10/11
= 10
= 5(1/1.2+1/2.3+1/3.4+...+1/9.10)
=5(1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10)
=5(1-1/10)
=5.9/10
=9/2
= 9/2
Nha bẹn :))))