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\(1\frac{1}{3}\cdot x+16\frac{3}{4}=13,25\)
\(\frac{4}{3}\cdot x=13,25-16\frac{3}{4}\)
\(\frac{4}{3}\cdot x=-3,5\)
\(x=-3,5:\frac{4}{3}\)
\(x=-2,625\)
\(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)
<=> \(\frac{10}{3}x=-30\)
=> x = -9
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)
<=> X=(-3)*3 => X=-9
Đáp số: x=-9
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Rightarrow\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-\dfrac{53}{4}-\dfrac{67}{4}\)
\(\Rightarrow\dfrac{10}{3}x=\dfrac{-120}{4}\)
\(\Rightarrow\dfrac{10}{3}x=-30\)
\(\Rightarrow x=-30:\dfrac{10}{3}\)
\(\Rightarrow x=-9\)
Vậy: ...
\(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)
\(\Leftrightarrow\dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}x=\dfrac{-120}{4}=-30\)
\(x=-30.\dfrac{3}{10}\)
\(x=\dfrac{-90}{10}=-9\)
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(=>\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3}x=-30\)
x = -30 : \(\frac{10}{3}\)
= > x = -9