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TA viết lại dưới dạng phân số :
\(\frac{2^{23}+2^{24}+2^{25}}{2^{18}+2^{19}+2^{20}}=\frac{2^{23}\left(1+2+2^2\right)}{2^{18}\left(1+2+2^2\right)}=\frac{2^{23}}{2^{18}}=2^5=32\)
[223(1+2+22)] : [218(1+2+22)]
=> (223.7) : (218.7)
=> (223:218)(7:7)
=> 25.1
=> 32
sau 58 ,7,50 ,2,-60 là phép tính khác .
mấy b giúp mk nha ?
a)4.15 + 28:7 - 620:618
= 60 + 4 - 62
= 60 + 4 - 36
= 28
b)(32+23.5) : 7
= (9+ 8.5):7
=(9+ 40):7
=49 : 7
=7
c)1125:1123-35:(110+23)-60
= 112 - 243 : (1+8)-60
= 121 -243 : 9 - 60
= 121 - 27 - 60
= 34
d)520:(515.6+515.19)
= 520:(515.(6+19)
= 520 : 515 . 25
= 55.25
= 3125.25
=78125
e)718: 716+22.23
= 72+ 25
= 49 + 32
= 81
f) 59.73 - 302+27.59
= 59.(73+27)-302
= 59.100- 900
= 5900 - 900
= 5000
Trần Tuyết Tâm
a, \(11^{25}\div11^{23}-3^5\div\left(1^{10}+2^3\right)-60\)
\(=11^{25}\div11^{23}-3^5\div\left(1+8\right)-60\)
\(=11^{25}\div11^{23}-3^5\div3^2-60\)
\(=11^2-3^3-60\)
\(=121-27-60\)
\(=94-60=34\)
b, \(2345-1000\div\left[19-2\left(21-18\right)^2\right]\)
\(=2345-1000\div\left[19-2.3^2\right]\)
\(=2345-1000\div\left[19-2.9\right]\)
\(=2345-1000\div1=2345-1000=1345\)
c, \(128-\left[68+8\left(37-35\right)^2\right]\div4\)
\(=128-\left[68+8.2^2\right]\div4\)
\(=128-\left[68+8.4\right]\div4\)
\(=128-\left[68+32\right]\div4\)
\(=128-100\div4=128-25=103\)
d, \(107-\left\{38+\left[7.3^2-24\div6+\left(9-7\right)^3\right]\right\}\div15\)
\(=107-\left\{38+\left[7.9-4+2^3\right]\right\}\div15\)
\(=107-\left\{38+\left[63-4+8\right]\right\}\div15\)
\(=107-\left\{38+\left[59+8\right]\right\}\div15\)
\(=107-\left\{38+67\right\}\div15\)
\(=107-105\div15\)
\(=107-7=100\)
e, \(50-\left[50-\left(2^3.5\right)\div2+3\right]\)
\(=50-\left[50-8.5\div2+3\right]\)
\(=50-\left[50-40\div2+3\right]\)
\(=50-\left[50-20+3\right]\)
\(=50-\left[30+3\right]\)
\(=50-33=17\)
Bài 2 :
a, \(5\left(x-9\right)=350-5^2\)
\(5\left(x-9\right)=350-25\)
\(5\left(x-9\right)=325\)
\(x-9=325\div5\)
\(x-9=65\)
\(\Rightarrow x=65+9\)
\(\Rightarrow x=74\)
Vậy x = 74
b, \(2\left(x-51\right)=2.2^3+20\)
\(2\left(x-51\right)=16+20\)
\(2\left(x-51\right)=36\)
\(x-51=36\div2\)
\(x-51=18\)
\(\Rightarrow x=18+51\)
\(\Rightarrow x=69\)
Vậy x = 69
c, \(2.3^x=162\)
\(\Rightarrow2.3^x=2.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy x = 4
\(\dfrac{2^{23}+2^{24}+2^{25}}{2^{18}+2^{19}+2^{20}}=\dfrac{2^{23}\left(1+2+2^2\right)}{2^{18}\left(1+2+2^2\right)}=2^5=32\)