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a, - 128 . (-25+89) + 128.(89-125)
= 128 . - (-25 +89) + 128 . (89 - 125)
= 128 . [-(-25+89)+(89 - 125)]
= 128. (25+89+89-125)
= 128 . (89.2+-100)=128.78=(120+8).(70+8)= 8.190=1520
a, [ 13-17 ].[-10]+[-7]0
=-4.[-10]+1
=40+1
=41
b, 72.[28-49] + 28.[-49-72]
=72.[-21]+28.[-121]
=-1512+[-3388]
=-4900
c, -65.[87-17] - 87.[17-65]
=-65.70-87.[-48]
=4550-[-4276]
=8726
d, -23.63+23.21-58.23
=23.(-63)+23.21-58.23
=23.(-63+23-58)
=23.(-40-58)
=23.(-98)
=-2254
e, 25.134+25.[-34]
=25.[134+(-34)]
=25.100
=2500
a) -65 .( 87 - 17 ) -87 .( 17 - 65 )
= ( - 65 ) . 87 + 17 - 87 . 17 + 65
= { ( - 65 ) + 65 } . 87 + 17
= 0 . 87 + 17
= 17
b) -215 . [ 14 + ( -236 ) ] + 215 . ( 14 - 236 )
= -215 . 14 + ( - 236 ) + 215 . 14 - 236
= [ ( - 215 ) + 215 ] . 14 + { ( - 236 - 236 }
= 0 . 14 + 0
= 0
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
A) ( 26-6).(-4)+31.(-7-13)=20.(-4)+31.(-20)=20.[-4+(-31)]=20.(-35)=-700
B)( -18).(55-24)-28.(44-68)=-18.31-28.(-24)=-588+672=84
C) (135+35).(-37)+37.(-42-58)=170.(-37)+37.(-100)=37.[-170+(-100)]=37.(-270)=-9990
D) -65.(87-17)-87.(71-65)=-65.60-87.6=-3900-522=-4422
E) [ 3.( -2)-(-8) ] . (-7).(-2).(-5)=2.(-7).(-2).(-5)=-14.(-2).(-5)=28.(-2)=-56
H) ( -25)+8+12+25=(-25+25)+(8+12)=0+20=20
K) 40 + 15 + (-10) + (-15)=(-15+15)+(-10+40)=0+30=30
F) -13+(-750)+(-17)+ 750=[-13+(-17)]+(-750+750)=-30+0=-30
J) ( -7) + ( -20 ) +35 + (-8)=-27+35+(-8)=8+(-8)=0
a, -87 + ( - 750 ) + 2018 - 13 + 750
= [ -87 + ( - 13 ) ] + [ - 750 + 750 ] + 2018
= ( - 100 ) + 0 + 2018 = 1918
b) ( 45 + 12 - 13 ) - ( 45 - 13 + 12 )
= 45 + 12 - 13 - 45 + 13 - 12
= 0
c) -15 x 56 + 43 x (-15)
= (-15) x ( 56 + 43 )
= ( - 15 ) x 99
= - 1485
e) 24 . ( 16 - 5 ) - 16 . ( 24 - 5 )
= 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5
= - 40
hai cau kia mk chiu
c) \(-15.56+43.\left(-15\right)\)
\(=-15.\left(-15\right)+\left(56+43\right)\)
\(=0+43+56\)
\(=0+99\)
\(=99\)
( mk chỉ bít làm mỗi câu c thôi thông cảm mk nhé )
a)
(-12)(-13)+13(-22) = 12.13 - 13.22 = 13(12-22)=13.(-10)=-130
b) 15(-14) +15(-6) + (-20).25 = 15[(-14)+(-6)]+(-20).25=15.(-20)+(-20).25=(-20)(15+25)=-20.40=-800
c) -65.(87-17)-87(17-65) =
a)(-12).(-13)+13.(-22)=12.13+13.(-22)=13.[12+(-22)]=13.(-10)=-130
b)15.(-14)+15.(-6)+(-20).25=15.[(-14)+(-6)]+(-20).25=15.(-20)+(-20).25=(-20).(15+25)=(-20).40=-800
c)-65.(87-17)-87.(17-65)=-65.87-(-65).17-87.17+87.65
=-65.87+65.17-87.17+87.65
=[(-65)+65].87+(65-87).17
=0.87+(-22).17
=0+(-374)=-374