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( 17 - 165 - 59 ) - ( 17 - 59 )
= ( -152 - 59 ) - ( -42 )
= ( -152 + -59 ) + 42
= ( - 211 ) + 42
= -169
23 . 7 + 23 . 14 - 8
= 8 .7 + 8 . 14 - 8 .1
= 8 . ( 7 + 14 -1 )
= 8 . 20
= 160
715 : 713 + 24 . 2 - 20080
= 49 + 16 . 2 - 1
= 49 + 32 - 1
= 81 - 1
= 80
27 - 3 . (x+2) = 6
3 . (x+2) = 27 - 6
3 . (x+2) = 21
x+2 = 21 : 3
x + 2 = 7
x = 7 - 2
x = 5
9|x| - 17 = 20 : |-2|
9|x| - 17 = |-20|
9 . |x| = |-20| + 17
9 . |x| = |-3|
|x| = 9 : |-3|
|x| = |-3|
Vậy |x| = |-3| , |3|
a/ ta có : 5.(27-17)2 - 611 : 69 = 5.102 - 611 :69
= 5.100 - 611-9 = 500 - 36 = 464
b/ ta có : (-15)+(-17) = -15 - 17 = -32
c/ ta có : 21.42 + 21.59 +21.52 = 21.(42 +59 +52 )
= 21. (16 + 59 + 25) = 21.100=2100
d/ ta có : 75 - (3.52 - 4.23 ) +20150 = 75 - (3.25 - 4.8) +1
= 75 - 43 +1 = 33
A) \(\frac{8^{15}.3^{17}}{4^{23}.9^9}=\frac{2^{45}.3^{17}}{2^{46}.3^{18}}=\frac{2^{45}.3^{17}}{2^{45}.3^{17}.\left(2.3\right)}=\frac{1}{6}\)
B)\(\frac{28^{15}.3^{17}}{84^{16}}=\frac{\left(2^2.7\right)^{15}.3^{17}}{\left(2^2.3.7\right)^{16}}=\frac{2^{30}.7^{15}.3^{17}}{2^{32}.3^{16}.7^{16}}=\frac{2^{30}.7^{15}.3^{16}.3}{2^{30}.7^{15}.3^{16}.\left(2^2.7\right)}=\frac{3}{28}\)
C) \(\frac{3^{10}+6^2}{5.3^8+20}=\frac{3^{10}+2^2.3^2}{5.3^8+2^2.5}=\frac{3^2.\left(3^8+2^2\right)}{5.\left(3^8+2^2\right)}=\frac{9}{5}\)
D) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{2^7.3^5.3}{2^7.3^5.2^4}=\frac{3}{16}\)
F) \(\frac{5^4.20^4}{25^4.4^5}=\frac{5^4.\left(2^2.5\right)^4}{\left(5^2\right)^4.\left(2^2\right)^5}=\frac{5^4.2^8.5^4}{5^8.2^{10}}=\frac{5^8.2^8}{5^8.2^8.2^2}=\frac{1}{4}\)
G) \(\frac{5^5+25^2+5^2}{-151}=\frac{5^5+5^4+5^2}{-151}=\frac{5^2.\left(5^3+5^2+1\right)}{-151}=\frac{25.151}{-151}=-25\)
A,\(\frac{8^{15}.3^{17}}{4^{23}.9^9}=\frac{\left(2^3\right)^{15}.3^{17}}{\left(2^2\right)^{23}.\left(3^2\right)^9}=\frac{2^{45}.3^{17}}{2^{46}.3^{18}}=\frac{1.1}{2.3}=\frac{1}{6}\)
B,\(\frac{28^{15}.3^{17}}{84^{16}}=\frac{28^{15}.3^{17}}{28^{16}.3^{16}}=\frac{1.3}{28.1}=\frac{3}{28}\)
C,\(\frac{3^{10}+6^2}{5.3^8+20}=\frac{3^{10}+3^2.2^2}{5.3^8+5.2^2}=\frac{3^2.\left(3^8+2^2\right)}{5.\left(3^8+2^2\right)}=\frac{3^2}{5}=\frac{9}{5}\)
D,\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)
F,\(\frac{5^4.20^4}{25^4.4^5}=\frac{5^4.5^4.4^4}{\left(5^2\right)^4.4^5}=\frac{5^8.4^9}{5^8.4^5}=\frac{1}{4}\)
G,xin lỗi mik ko lm đc câu này.
Nhưng mik cũng đã cố gắng làm giúp bn mấy câu trên. k cho mik nha.
Bạn Hương Giang nói đúng đấy , vừa không muốn làm , vừa rối mắt . Tớ khong có ý muốn gây sự với bạn nha , chỉ là nhận xét thôi .
\(a.=17-165-59-17-59\)
\(=0-165-0\)
\(=-165\)
\(b.=7^2+2^5-1\)
\(=49+32-1\)
\(=80\)
\(c.=2^3\left(4+14-1\right)\)
\(=2^3.17\)
\(=8.17\)
\(=136\)
\(d.3\left(x+2\right)=21\)
\(x+2=7\)
\(x=5\)
\(e.9|x|-17=20:2\)
\(9|x|-17=10\)
\(9|x|=27\)
\(|x|=3\)
\(\Rightarrow x=\pm3\)
(17-165-59) -(17-59)
= -( 207 ) - ( - 42 )
= - ( 207 - 42 )
= -165
715:713+24.2-20080
= 72 + 25 - 1
= 49 + 32 - 1
= 80
23.7+23.14-8
= 23 . ( 7 + 14 ) - 8
= 23 . 21 - 8
= 8 . 21 - 8
= 168 - 8
= 160
27-3 (x+2) = 6
3 ( x + 2 ) = 27 - 6
3 ( x +2 ) = 21
x + 2 = 21 : 3
x + 2 = 7
x = 7 - 2
x = 5
Vậy x = 5
9|x|-17=20:|-2|
9 |x| - 17 = 20 : 2
9 |x| - 17 = 10
9 |x| = 10 + 17
9 |x| = 27
|x| = 27 : 9
|x| = 3
x = -3
Vậy x = -3
Hok tốt !!