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Giải:
Bài 1:
\(707-3\left(x+3\right)=407\)
\(\Leftrightarrow3\left(x-3\right)=300\)
\(\Leftrightarrow x+3=100\)
\(\Leftrightarrow x=97\)
Vậy \(x=97\).
Bài 2:
a) \(143-43.\left[\left(25:5\right)^2-5^2\right]\)
\(=143-43.\left(5^2-5^2\right)\)
\(=143-43.1\)
\(=143-43=100\)
b) \(7:7+49\left(2^3.15-5.4\right)\)
\(=1+49.\left(120-20\right)\)
\(=1+49.100\)
\(=4901\)
c) \(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)
\(=\left(8.9^4+9^4.5\right):\left(9^2.10-9^2\right)\)
\(=\left[9^4\left(8+5\right)\right]:\left[9^2\left(10-1\right)\right]\)
\(=9^4.13:9^3\)
\(=9.13=117\)
Chúc bạn học tốt!
36 x 12 + 36 x 45 + 36 x 33
= 36 x (12 + 45 + 33)
= 36 x 90
= 3240
b) 78 x 31 + 78 x 24 + 78 x 17 + 22 x 72
=78 x (31 + 24 + 17) + 22 x 72
= 78 x 72 + 22 x 72
= (78 + 22) x 72
= 100 x 72
= 7200
c) ( 34 - 17 )2 - 23 x 32
\(=17^2-8.9\)
\(=289-72\)
\(=217\)
a) 5 ( x + 35 ) = 515
x + 35 = 103
x = 68
b) 96 - 3(x+1) = 49
3(x+1) = 47
x + 1 = 47/3
x = 44/3
c) 12x - 33 = 3^2 * 3^3
12x - 33 = 243
12x = 276
x = 23
5 ( x + 35 ) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
96 - 3( x + 1 ) = 49
3( x + 1 ) = 96 - 49
3( x + 1 ) = 47
x + 1 = 47/3
x = 47/3 - 1
x = 44/3
12x - 33 = 32 . 33
12x - 33 = 35
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
Giải:
\(707-3\left(x+3^4\right)=407\)
\(\Leftrightarrow3\left(x+3^4\right)=300\)
\(\Leftrightarrow x+3^4=100\)
\(\Leftrightarrow x+81=100\)
\(\Leftrightarrow x=100-81=19\)
Vậy \(x=19\).
Chúc bạn học tốt!
707 - 3 . ( x + 34 ) = 407
707 - 3 . ( x + 81 ) = 407
3 . (x + 81) = 707 - 407
3 . (x + 81) = 300
x + 81 = 300 : 3
x + 81 = 100
x = 100 - 81
x = 9.
a) 20-( x - 5 ) x2 = 2
( x - 5 ) x2 = 20-2=18
x - 5 = 18 : 2
x - 5 = 9
x = 9+5
x = 14.
b) 150 : ( 38 - 2x ) = 5
38 - 2x = 150 : 5 = 30
2x = 38 - 30 = 8
x = 8 : 2
x = 4.
\(\left(x+2\right)^5=2^{10}\)
\(\left(x+2\right)^5=\left(2^2\right)^5\)
\(\left(x+2\right)^5=4^5\)
\(\Rightarrow x+2=4\)
\(\Rightarrow x=4-2\)
\(\Rightarrow x=2\)
\(1+2+3+...+x=78\)
Ta có :
\(\frac{x\cdot\left(x+1\right)}{2}=78\)
\(x\cdot\left(x+1\right)=78\cdot2\)
\(x\cdot\left(x+1\right)=156\)
Vì \(x\cdot\left(x+1\right)\)là tích của 2 số tự nhiên liên tiếp
\(\Rightarrow12\cdot13=156\)
\(\Rightarrow x=12\)
\(\left(x+1\right)^2=\left(x+1\right)^0\)
\(\left(x+1\right)^2=1\)
\(\left(x+1\right)^2=1^2\)
\(\Rightarrow x+1=1\)
\(\Rightarrow x=1-1\)
\(\Rightarrow x=0\)
\(\left(2+x\right)+\left(4+x\right)+\left(6+x\right)+...+\left(52+x\right)=780\)
\(\left(x+x+x+...+x\right)+\left(2+4+6+...+52\right)=780\)
\(26x+\frac{\left(52+2\right)\cdot26}{2}=780\)
\(26x+702=780\)
\(26x=780-702\)
\(26x=78\)
\(x=78:26\)
\(x=3\)
Vậy \(x=3\)
Chúc bạn học tốt !!!
707 - 3( x + 34 ) = 407
=> 3( x + 81 ) = 300
=> x + 81 = 100
=> x = 19
127 + 3( x + 17 ) = ( 47 : 45 )2
=> 3( x + 17 ) = ( 42 )2 - 127
=> 3( x + 17 ) = 256 - 127
=> 3( x + 17 ) = 129
=> x + 17 43
=> x = 26
x - 6 - ( 48 - 24. 2 : 6 - 3 ) = 100
x - 6 - ( 48 - 2 - 3 ) = 100
x - 6 - 43 = 100
x - 49 = 100
x = 149
[ ( 6x - 39 ) : 3 ] . 28 = 5628
( 6x - 39 ) : 3 = 201
6x - 39 = 603
6x = 642
x = 107
Chúc em hok tốt
Study well
\(707-3.(x+3^4)=407\)
\(\Rightarrow\)\(707-3.(x+81)=407\)
\(\Rightarrow\)\(3.(x+81)=707-407\)
\(\Rightarrow\)\(3.\left(x+81\right)=300\)
\(\Rightarrow\)\(\left(x+81\right)=300:3\)
\(\Rightarrow\)\(\left(x+81\right)=100\)
\(\Rightarrow\) \(x=100-81\)
Xin lỗi vì tôi có việc bận nên tí nữa sẽ làm tiếp
\(\Rightarrow\) \(x=19\)
a/ 12x - 33 = 32 . 32
=> 12x - 33 = 35 = 243
=> 12x = 243 + 33 = 276
=> x = 276 : 12 = 23
b/ 148 + (78 + x) = 244
=> 78 + x = 148 - 244 = -96
=> x = -96 - 78 = -174
c/ 45 - x = 49 + 52
=> 45 - x = 101
=> x = 45 - 101 = -56
d/ 707 - 3(x + 34) = 407
=> 3(x + 34) = 707 - 407 = 300
=> x + 34 = 300 : 3 = 100
=> x = 100 - 34 = 66
e/ 25.3 - x = 104
=> 75 - x = 104
=> x = 75 - 104 = -29