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a/ 100 . 37 + 37. 37 + 200 . 63 - 63 . 63\
= 37 .[ 100+ 37 ] + 63 . [ 200 - 63 ]
= 37. 137 + 63 . 137
= 137. [ 37 + 63 ]
= 137 . 100 = 13700
b/ 84 + 14 .6 + 7 . 12 + 21. 4 + 3.28
= 84 + 84 + 84 + 84 +84
= 84. 5 = 420
[ dấu " ." là " x" nha ] đừng quên tích cho tui
a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
c) \(A=\frac{4}{1.3}+\frac{4}{3.5}+\frac{4}{5.7}+...+\frac{4}{49.51}\)
\(A=2.\left(\frac{2}{1.3}+\frac{2}{2.5}+\frac{2}{5.7}+...+\frac{2}{49.51}\right)\)
\(A=2.\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{51-49}{49.51}\right)\)
\(A=2.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=2.\left(1-\frac{1}{51}\right)=2.\frac{50}{51}=\frac{100}{51}\)
Vậy \(A=\frac{100}{51}\)
d) \(B=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
\(B=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)
\(B=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(B=1-\frac{1}{10}=\frac{9}{10}\)
Vậy \(B=\frac{9}{10}\)