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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}-2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}\\ =\left(0,75-0,6-2,75-2,2\right)+3\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)+11\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)\\ =\left(-4,8\right)+\left(3+11\right)\cdot\dfrac{20}{91}\\ =-4,8+14\cdot\dfrac{20}{91}\\ =-\dfrac{24}{5}+\dfrac{40}{13}\\ =-\dfrac{112}{65}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)
\(=\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{7}-\frac{3}{13}}{\frac{11}{4}+\frac{11}{5}-\frac{11}{7}-\frac{11}{13}}\)
\(=\frac{3.\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}{11.\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}\)
\(=\frac{3}{11}\)
\(\frac{0,75-0,6-\frac{3}{7}+\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)
\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)
\(=\frac{3}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{3}}\)
A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{\frac{11}{3}\left(0,75+0,6-\frac{3}{7}-\frac{3}{13}\right)}\)
A=\(\frac{1}{\frac{11}{3}}\)
A= \(\frac{3}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)
P = 0,75 - 0,6 +3/7 + 3/13
= 3/4 - 3/5 +3/7 +3/13
= \(\frac{1365-1092+780+420}{1820}\)
=1473
trên có nghĩa là dấu gạch ngang ở giữa
3/4-3/5+3/7+3/13 trên 11/4-11/5+11/7+11/3=3x1/4-3x1/5+3x1/7+3x1/13 trên 11x1/4-11x1/5+11x1/7+11x1/13=3x(1/4-1/5+1/7+1/13) trên 11x(1/4-1/5+1/7+1/13)=3/11
vay P=3/11