Question

[Dương Hoàng]

p= 3ab+2b mũ 2 / -b mũ 2 +5ab (a,b khác 0 ) với a mũ 2 - 3ab =0

Answer 1

[Nguyễn Huy Tú]

\(P=\dfrac{3ab+2b^2}{-b^2+5ab}=\dfrac{b\left(3a+2b\right)}{-b\left(b-5a\right)}=\dfrac{-\left(3a+2b\right)}{b-5a}\)