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A=2^2+2^2+2^3+...+2^20
2A=2^3+2^3+2^4+...+2^21
2A-A=2^3+2^3+2^4+...+2^21-2^2-2^2-2^3-...-2^20
A=8+2^21-4-4=2^21
a) \(\text{2(x-51)=2.2^2+20}\)
\(2\left(x-51\right)=2.4+20\)
\(2\left(x-51\right)=28\)
\(x-51=28\div2\)
\(x-51=14\)
\(x=14+51\)
\(\text{b)3.(x+1)-26=541}\)
\(3.\left(x+1\right)=541+26\)
\(3\cdot\left(x+1\right)=567\)
\(x+1=567\div3\)
\(x+1=189\)
\(x=189-1\)
\(x=188\)
\(x=65\)
\(\text{c)4(x-3)=7^2-1^10}\)
\(4\left(x-3\right)=49-1\)
\(4\left(x-3\right)=48\)
\(x-3=48\div4\)
\(x-3=12\)
\(x=12+3\)
\(x=15\)
\(\text{e)2x-138=2^3.3^2}\)
\(2x-138=8\cdot9\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=210\div2\)
\(x=105\)
\(\text{f)(x-1)^4=16}\)
\(\left(x-1\right)^4=2^4\)
\(x-1=2\)
\(x=2+1\)
\(x=3\)
b) Ta có: (2N+2).N:2 = 210
= N.(N+1)
Ta có; N.(N+1) =210
Mà 210 = 2.3.5.7 = (2.4).(3.5) = 14.15
Suy ra N.(N+1) =14.15
Vậy N = 14
Tick cái nha!
2x - 138 = 23 . 32
\(\Rightarrow\) x - 69 = 22 . 9 = 4 . 9
\(\Rightarrow\) x - 69 = 36
\(\Rightarrow\) x = 105
231 - (x - 6) = 1339 : 13
\(\Rightarrow\) 231 - (x - 6) = 103
\(\Rightarrow\) x - 6 = 128
\(\Rightarrow\) x = 134
a
Bcnn của các mẫu là:2^4.3^2.5^2.7
Thừa số phụ
(2^4.3^2.5^2.7):(2^2.3.5^2)=84
(2^4.3^2.5^2.7):(2^4.3^2.5.7)=5
Mẫu chung:2^4.3^2.5^2.7
Ta có
13/2^2.3.5^2=13.84/2^2.3.5^2.84=1092/25200
11/2^4.3^2.5.7=11.5/2^4.3^2.5.7.5=55/25200
\(\left\{210:\left[16+3.\left(6+3.2^2\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.\left(6+12\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.18\right]\right\}-3\)
\(=\left\{210:\left[16+54\right]\right\}-3\)
\(=\left\{210:70\right\}-3=3-3=0\)