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\(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
\(1,12x^2y-27y^3=3y\left(4x^2-9y^2\right)=3y\left(2x+3y\right)\left(2x-3y\right)\\ 2,4x^2-36=4\left(x^2-9\right)=4\left(x-3\right)\left(x+3\right)\\ 3,x^2-4x+4-y^2=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\\ 4,\left(3x+1\right)^2-\left(x-2\right)^2=\left(3x+1-x+2\right)\left(3x+1+x-2\right)=\left(2x+3\right)\left(4x-1\right)\)
\(1,=3y\left(4x^2-9y^2\right)=3y\left(2x+3y\right)\left(2x-3y\right)\)
\(2,=4\left(x^2-9\right)=4\left(x-3\right)\left(x+3\right)\)
\(3,=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x-y+2\right)\)
\(4,=\left(3x+1-x+2\right)\left(3x+1+x-2\right)=\left(2x+3\right)\left(4x-1\right)\)
1) x2- 3x - 6x +18
= (x2- 3x )-(6x -18 )
= x(x-3)- 6(x-3)
= (x-6)(x-3)
Ta có: \(6x^2-7x+2=6x^2-3x-4x+2\)
\(=\left(6x^2-3x\right)-\left(4x-2\right)\)
\(=3x\left(2x-1\right)-2\left(2x-1\right)\)
\(=\left(2x-1\right)\left(3x-2\right)\)