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chuyển đổi lại : (7x - 3) : 12 = 13
=> (7x - 3) = 13 * 12
=> 7x - 3 = 156
=> 7x = 159
=> x= 159/7
[(7x - 31) : 5] * 36 = 7236
=> [(7x - 31) : 5] = 7236 : 36 = 201
=> (7x - 31) : 5 = 201
=> 7x - 31 = 1005
=> 7x = 1036
=> x = 148
1 + 2 + 3 + 4 + 5 +... + 100 + x = 5350
SSH : \(\left(100-1\right):1+1=100\)
=> tổng : \(\frac{\left(1+100\right)\cdot100}{2}=5050\)
=> 5050 + x = 5350
=> x = 5350 - 5050 = 300
80 - 9(x - 4) = 35
=> 9(x - 4) = 80 - 35 = 45
=> x - 4 = 45 : 9
=> x - 4 = 5
=> x = 9
(3x - 21) : 4 + 108 = 114
=> (3x - 21) : 4 = 114 - 108 = 6
=> 3x - 21 = 24
=> 3x = 45
=> x = 15
[(6x - 72) : 2 - 84]*14 = 2814
=> [(6x - 72) : 2 - 84] = 201
=> (6x - 72) : 2 - 84 = 201
=> (6x - 72) : 2 = 285
=> 6x - 72 = 570
=> 6x = 642
=> x = 107
28x + 12x = 80
=> 40x = 80
=> x = 2
249 - 7(1 + x) = 200
=> 7(1 + x) = 49
=> 1 + x = 7
=> x = 6
20 - [(x - 5) * 7 + 4] = 2
=> [(x - 5) * 7 + 4] = 18
=> (x - 5)*7 + 4 = 18
=> (x - 5) * 7 = 14
=> x - 5 = 2
=> x = 7
\(\frac{7x-33}{12}=13\)
\(7x-33=13\cdot12\)
\(7x-33=156\)
\(7x=156+33\)
\(7x=189\)
\(x=\frac{189}{7}=27\)
\(\frac{7x-31}{5}\cdot36=7236\)
\(\frac{7x-31}{5}=\frac{7236}{36}\)
\(\frac{7x-31}{5}=201\)
\(7x-31=201\cdot5\)
\(7x-31=1005\)
\(7x=1005+31\)
\(7x=1036\)
\(x=\frac{1036}{7}=148\)
\(1+2+3+4+5+..+100+x=5350\)
\(\left(1+2+3+4+5+...+100\right)+x=5350\)
Phần 1 + 2 + 3 + 4 + 5 + ... + 100 có số số hạng là :
\(\frac{100-1}{1}+1=100\) ( số hạng )
\(\Rightarrow\frac{\left(100+1\right)\cdot100}{2}+x=5350\)
\(5050+x=5350\)
\(x=5350-5050=300\)
\(80-9\left(x-4\right)=35\)
\(9\left(x-4\right)=80-35\)
\(9\left(x-4\right)=45\)
\(x-4=\frac{45}{9}\)
\(x-4=5\)
\(x=5+4=9\)
\(\frac{3x-21}{4}+108=114\)
\(\frac{3x-21}{4}=114-108\)
\(\frac{3x-21}{4}=6\)
\(3x-21=6\cdot4\)
\(3x-21=24\)
\(3x=24+21\)
\(3x=45\)
\(x=\frac{45}{3}=15\)
\(14\left(\frac{6x-72}{2}-84\right)=2814\)
\(3x-36-84=\frac{2814}{14}\)
\(3x-120=201\)
\(3x=201+120\)
\(3x=321\)
\(x=\frac{321}{3}=107\)
\(28x+12x=80\)
\(x\left(28+12\right)=80\)
\(x\cdot40=80\)
\(x=\frac{80}{40}=2\)
\(249-7\left(1+x\right)=200\)
\(-7\left(1+x\right)=200-249\)
\(-7\left(1+x\right)=-49\)
\(1+x=\frac{-49}{-7}\)
\(1+x=7\)
\(x=7-1=6\)
\(20-7\left(x-5\right)+4=2\)
\(20-7\left(x-5\right)=2-4\)
\(20-7\left(x-5\right)=-2\)
\(-7\left(x-5\right)=-2-20\)
\(-7\left(x-5\right)=-22\)
\(x-5=\frac{-22}{-7}\)
\(x=\frac{22}{7}+5=\frac{57}{7}\)
a) \(124+\left(118+x\right)=217\)
\(118+x=217-124\)
\(118+x=93\)
\(x=-25\)
vay \(x=-25\)
b) \(\left[\left(6x-72\right):2-84\right].28=5628\)
\(\left(6x-72\right):2-84=5628:28\)
\(\left(6x-72\right):2-84=201\)
\(\left(6x-72\right):2=201+84\)
\(\left(6x-72\right):2=285\)
\(6x-72=285.2\)
\(6x-72=570\)
\(6x=642\)
\(x=107\)
vay \(x-107\)
c) \(71.2-\left(2x+5\right).6=100\)
\(142-\left(2x+5\right).6=100\)
\(\left(2x+5\right).6=142-100\)
\(\left(2x+5\right).6=42\)
\(2x+5=7\)
\(2x=2\)
\(x=1\)
vay \(x=1\)
a) \(\dfrac{3}{4}\times x:\dfrac{1}{2}=\dfrac{4}{5}\)
\(\dfrac{3}{4}\times x=\dfrac{4}{5}\times\dfrac{1}{2}\)
\(\dfrac{3}{4}\times x=\dfrac{2}{5}\)
\(x=\dfrac{2}{5}:\dfrac{3}{4}\)
\(x=\dfrac{8}{15}\)
b) \(\left(14-x:6\right)\times7=84\)
\(14-x:6=84:7\)
\(14-x:6=12\)
\(x:6=14-12\)
\(x:6=2\)
\(x=6\times2=12\)
c) \(x\times1,5:2,4=0,3\)
\(x\times1,5=0,3\times2,4\)
\(x\times1,5=0,72\)
\(x=0,72:1,5\)
\(x=0,48\)
d) Thiếu x
a)\(3:\left(2x+1\right)=72-69\)
\(3:\left(2x+1\right)=3\)
\(2x+1=3:3\)
\(2x+1=1\)
\(2x=1-1\)
\(2x=0\)
\(x=0:2\)
\(x=0\)
các bài còn lại giống như câu a nha nếu ko biết thì comment lại minhf sẽ giải cho . Nhớ k cho mình nha
Câu 1:
$150\vdots x; 84\vdots x, 30\vdots x$
$\Rightarrow x=ƯC(150,84,30)$
$\Rightarrow ƯCLN(150,84,30)\vdots x$
$\Rightarrow 6\vdots x$. Kết hợp với điều kiện $x<16$ suy ra:
$x\in \left\{1; -1; 2; -2; 3;-3;6;-6\right\}$
Câu 2:
$x\vdots 15; x\vdots 14; x\vdots 20$
$\Rightarrow x=BC(15,14,20)$
$\Rightarrow x\vdots BCNN(15,14,20)$
$\Rightarrow x\vdots 420$
$\Rightarrow x=420k$ với $k$ là số tự nhiên.
Mà $400\leq x\leq 1200$
$\Rightarrow 400\leq 420k\leq 1200$
$\Rightarrow 0< k< 3$
Mà $k$ là stn nên $k=1$ hoặc $k=2$
$\Rightarrow x=420.1=420$ hoặc $x=420.2=840$
( 6x - 72 : 2 - 84) x 28 = 5628
(6x - 36 - 84) = 5628 : 28
6x - 36 - 84 = 201
6x = 201 + (36 + 84)
6x = 321
x = 53,5
`@` `\text {Ans}`
`\downarrow`
`1,`
`a)`
`5 \times 72 \times 10 \times 2`
`= 5 \times 2 \times 10 \times 72`
`= 10 \times 10 \times 72`
`= 100 \times 72`
`= 7200`
`b)`
`40 \times 125`
`= 4 \times 10 \times 25 \times 5`
`= (5 \times 10) \times (4 \times 25)`
`= 50 \times 100`
`= 5000`
`c)`
`4 \times 2021 \times 25`
`= (4 \times 25) \times 2021`
`= 100 \times 2021`
`= 202100`
`d)`
`16 \times 6 \times 25`
`= 4 \times 4 \times 6 \times 25`
`= (4 \times 25) \times 4 \times 6`
`= 100 \times 24`
`= 2400`
`2,`
`a)`
`24 \times 57 + 43 \times 24`
`= 24 \times (57+43)`
`= 24 \times 100`
`= 2400`
`b)`
`12 \times 19 + 80 \times 12 +12`
`= 12 \times (19 + 80 + 1)`
`= 12 \times 100`
`= 1200`
`c)`
`(36 \times 15 \times 169) \div (5 \times 18 \times 13)`
`= 36 \times 15 \times 169 \div 5 \div 18 \div 13`
`= 6 \times 6 \times 3 \times 5 \times 13 \times 13 \div 5 \div 3 \times 6 \div 13`
`= (6 \div 6) \times (3 \div 3) \times (5 \div 5) \times (13 \div 13) \times 6 \times 13`
`= 6 \times 13`
`= 78`
`d)`
`(44 \times 52 \times 60) \div ( 11 \times 13 \times 15)`
`= 44 \times 52 \times 60 \div 11 \div 13 \div 15`
`= 4 \times 11 \times 13 \times 4 \times 15 \times 4 \div 11 \div 13 \div 15`
`= (11 \div 11) \times (13 \div 13) \times (15 \div 15) \times 4 \times 4 \times`
`= 4 \times 4 \times 4`
`= 64`
`3,`
`a)`
`x - 280 \div 35 = 5 \times 54`
`x - 8 = 270`
`x = 270 + 8`
`x = 278`
`b)`
`(x - 280) \div 35 = 54 \div 4`
`(x - 280) \div 35 = 13,5`
`x - 280 = 13,5 \times 35`
`x - 280 = 472,5`
`x = 472,5 + 280`
`x = 752,5`
`c)`
`(x - 128 + 20) \div 192 = 0`
`x - 128 + 20 = 0 \times 192`
`x - 128 + 20 = 0`
`x - 108 = 0`
`x = 0 + 108`
`x = 108`
`d)`
`4 \times (x + 200) = 460 + 85 \times 4`
`4 \times (x+200) = 460 + 340`
`4 \times (x+200) = 800`
`x + 200 = 800 \div 4`
`x + 200 = 200`
`x = 200 - 200`
`x = 0`
`4,`
`a)`
`7/12 - 5/12`
`= (7 - 5)/12`
`= 2/12`
`= 1/6`
`b)`
`8/11 + 19/11`
`= (8+19)/11`
`= 27/11`
`c)`
`3/8 + 5/12`
`= 9/24 + 10/24`
`= 19/24`
`d)`
`3/4 + 7/12`
`= 9/12 + 7/12`
`= 16/12`
`= 4/3`
`5,`
`a)`
`x - 6/7 = 5/2`
`x = 5/2 + 6/7`
`x = 47/14`
`b)`
`12/7 \div x + 2/3 = 7/5`
`12/7 \div x = 7/5 - 2/3`
`12/7 \div x = 11/15`
`x = 12/7 \div 11/15`
`x = 180/77`
`@` `\text {Kaizuu lv uuu}`
\(a)\left(80\times96+40\times1808\right):1000\)
\(=\left(80\times96+40\times2\times904\right):1000\)
\(=\left(80\times96+80\times904\right):1000\)
\(=80\times\left(96+904\right):1000\)
\(=80\times1000:1000\)
\(=80\)
\(b)\) em xem lại đề xem có sai gì không em.
\(c)10\times12\times14\times16\times\left(88\times17-44\times34\right)\)
\(=10\times12\times14\times16\times\left(44\times2\times17-44\times2\times17\right)\)
\(=10\times12\times14\times16\times0\)
\(=0\)
a)230+[(x-5)+16]=315.8
<=>230+[(x-5)+16]=2520
<=>(x-5)+16=2290
<=>x-5=2274
<=>x=2279
b)20-[(x-5)+4]=2
<=>(x-5)+4=18
<=>x-5=14
<=>x=19
c)[(6x-72):2-84].14=2814
<=>(6x-72):2-84=201
<=>(6x-72):2=285
<=>6x-72=570
<=>6x=642
<=>x=107
Những dạng này ko khó chút nào em động não tí là ra à :D
a)230+[(x-5)+16]=315.8
<=>230+[(x-5)+16]=2520
<=>(x-5)+16=2290
<=>x-5=2274
<=>x=2279
b)20-[(x-5)+4]=2
<=>(x-5)+4=18
<=>x-5=14
<=>x=19
c)[(6x-72):2-84].14=2814
<=>(6x-72):2-84=201
<=>(6x-72):2=285
<=>6x-72=570
<=>6x=642
<=>x=107
Những dạng này ko khó chút nào em động não tí là ra à :D