Question

[Ngô Hoàng Trọng Tín]

Mình nhờ các bạn giải mình giúp bài này nha!

\(\frac{-1}{7}\)\(\times\)\(\left(9\frac{1}{2}-8,75\right)\div\frac{2}{7}+62,5\%\)    \(\div1\frac{2}{3}\) 

Answer 1

[Kiệt Nguyễn]

\(\frac{-1}{7}\left(9\frac{1}{2}-8,75\right)\div\frac{2}{7}+62,5\%\div1\frac{2}{3}\)

\(=\frac{-1}{7}\left(\frac{19}{2}-8,75\right).\frac{7}{2}+62,5\%\div\frac{5}{3}\)

\(=\frac{-1}{7}\left(\frac{19}{2}-\frac{875}{100}\right).\frac{7}{2}+62,5\%.\frac{3}{5}\)

\(=\frac{-1}{2}\left(\frac{38}{4}-\frac{35}{4}\right)+\frac{625}{100}.\frac{3}{5}\)

\(=\frac{-1}{2}.\frac{3}{4}+\frac{25}{4}.\frac{3}{5}\)

\(=\frac{-3}{8}+\frac{75}{20}\)

\(=\frac{-15}{40}+\frac{150}{40}\)

\(=\frac{135}{40}=\frac{27}{8}\)