Question

[Phạm Thanh Hải]

\(\left(3x+1\right)^2:\left(\dfrac{-1}{4}\right)=\dfrac{-49}{4}\)

Answer 1

[Nguyễn Huy Tú]

\(\left(3x+1\right)^2:\left(-\dfrac{1}{4}\right)=\left(\dfrac{-49}{4}\right)\)

\(\Rightarrow\left(3x+1\right)^2=\dfrac{49}{16}\)

\(\Rightarrow\left[{}\begin{matrix}3x+1=\dfrac{7}{4}\\3x+1=\dfrac{-7}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{-11}{12}\end{matrix}\right.\)

Vậy \(x=\dfrac{1}{4}\) hoặc \(x=\dfrac{-11}{12}\)

Answer 2

[Phạm Thanh Hải]

\(\dfrac{7}{3}ở\) đâu ra

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