Question

[minh ngọc]

Khử mẫu của bthuc lấy căn
a)√3/2a^2
b)√1/600
  √11/540
   √3/50
   √5/98
c)√(1-√3)^2/27
d)√2/3
e)√x^2/5
f) √3/x
g)√x^2-  x^2/7
h)ab√a/b
i)a/b√a/b
  √1/b +1/b^2
   √9a^3/36b
    3ab√2/ab

 

 

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\sqrt{\dfrac{3}{2}a^2}=\left|a\right|\cdot\dfrac{\sqrt{6}}{2}\)

b: \(\sqrt{\dfrac{1}{600}}=\dfrac{1}{10\sqrt{6}}=\dfrac{\sqrt{6}}{60}\)

\(\sqrt{\dfrac{11}{540}}=\dfrac{\sqrt{165}}{90}\)

\(\sqrt{\dfrac{3}{50}}=\sqrt{\dfrac{6}{100}}=\dfrac{\sqrt{6}}{10}\)

\(\sqrt{\dfrac{5}{98}}=\sqrt{\dfrac{10}{196}}=\dfrac{1}{14}\cdot\sqrt{10}\)

c: \(\sqrt{\dfrac{\left(1-\sqrt{3}\right)^2}{27}}=\dfrac{\sqrt{3}-1}{3\sqrt{3}}=\dfrac{3-\sqrt{3}}{9}\)

d: căn 2/3=căn 6/9=1/3*căn 6

e: \(\sqrt{\dfrac{x^2}{5}}=\sqrt{\dfrac{5x^2}{25}}=\pm\dfrac{x\sqrt{5}}{5}\)

f: \(\sqrt{\dfrac{3}{x}}=\sqrt{\dfrac{3x}{x^2}}=\dfrac{\sqrt{3x}}{\left|x\right|}\)